Knowledge / Biotechnology Engineering / Genetics

Genetics

Biotechnology Engineering (B.E./B.Tech) · Biology core · free study notes for exams, placements and interviews

In short

Genetics is the study of how traits are stored in genes, transmitted from parents to offspring and altered by mutation and recombination. It supplies the logic behind plant and animal breeding, diagnostics, pharmacogenomics, GMO development and population screening, so every biotechnology degree treats it as a core paper. It is examined heavily in GATE BT (Mendelian ratios, linkage mapping, Hardy-Weinberg, pedigrees), CSIR-UGC NET Life Sciences, ICMR/DBT-BET and university semester papers, usually as numerical problems. Employers who test it include Dr Reddy's, Biocon, Serum Institute, Syngene, Thermo Fisher, MedGenome, Strand Life Sciences, Mahyco, Rasi Seeds, Nuziveedu and public labs such as CCMB, NIPGR, ICAR institutes and NIBMG.

Explained

Mendelian basis of inheritance

Deviations from Mendelian ratios (allelic and gene interactions)

Linkage, crossing over and mapping

Sex determination, sex linkage and pedigrees

Mutation and chromosomal aberrations

Population and quantitative genetics

Key points

Formulas and examples

Number of gamete types from a heterozygote = 2n ; genotypes in F2 = 3n ; phenotypes in F2 (complete dominance) = 2n (n = number of heterozygous gene pairs)
Recombination frequency RF (%) = (number of recombinant progeny / total progeny) × 100 ; 1% RF = 1 cM (map unit)
Expected double crossovers = RF(A-B) × RF(B-C) × total progeny (frequencies as decimals)
Coefficient of coincidence CoC = observed DCO / expected DCO ; Interference I = 1 − CoC
Chi-square χ² = Σ (O − E)² / E ; df = (classes − 1) ; reject the hypothesis if χ² > critical value (3.84 for df = 1, 7.81 for df = 3, at p = 0.05)
Hardy-Weinberg: p + q = 1 ; p² + 2pq + q² = 1 (p², 2pq, q² = frequencies of AA, Aa, aa)
V_P = V_G + V_E + V_GE ; H² = V_G/V_P ; h² = V_A/V_P ; Response to selection R = h² × S (S = selection differential, same units as the trait)
Minimum number of polygenes contributing: F2 extreme-phenotype fraction = (1/4)n , so n = log(1/fraction)/log 4

Example 1 — Dihybrid test cross and chi-square. A pea plant round-yellow (RrYy) is test crossed to wrinkled-green (rryy). Progeny observed: 55 round-yellow, 51 round-green, 49 wrinkled-yellow, 45 wrinkled-green; total 200.

Example 2 — Recombination frequency. In a *Drosophila* test cross for body colour and wing size, 1,000 progeny give 415 wild type, 405 black-vestigial, 92 black-normal, 88 wild-vestigial.

Example 3 — Three-point cross, gene order and interference. A trihybrid is test crossed; 1,000 progeny:

ClassCountType
+ + +348Parental
a b c342Parental
+ b c72SCO (a-b)
a + +68SCO (a-b)
+ + c80SCO (b-c)
a b +76SCO (b-c)
+ b +8Double CO
a + c6Double CO

Example 4 — Hardy-Weinberg carrier frequency. β-thalassaemia major (autosomal recessive) affects about 1 in 2,500 newborns in a population.

Example 5 — Heritability and response to selection. In a rice population, mean grain yield is 4.0 t/ha with V_P = 0.50, V_A = 0.20. Plants selected for the next generation average 4.8 t/ha.

PatternGiveaway in the pedigreeExample
Autosomal dominantEvery generation affected; affected child has an affected parentHuntington disease
Autosomal recessiveSkips generations; consanguinity common; both sexes equalβ-thalassaemia, sickle-cell
X-linked recessiveMostly males; no male-to-male; via carrier mothersHaemophilia A, DMD
X-linked dominantAffected father → all daughters, no sonsVitamin D-resistant rickets
Y-linkedFather → all sons onlySome infertility factors
MitochondrialAffected mother → all children; never from fatherLHON, MELAS

Where it is used

Interview questions

Common mistakes

Related topics

Cell biology · Molecular biology: replication, transcription and translation · Biochemistry: biomolecules and enzymes · Microbiology basics · Plant and animal biotechnology · Bioinformatics and genomics

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