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Spectroscopy: UV, IR, NMR and mass

Pharmacy (B.Pharm) · Pharmaceutical chemistry and analysis · free study notes for exams, placements and interviews

In short

Spectroscopy studies how a drug molecule interacts with electromagnetic radiation — UV-visible light excites electrons, infrared excites bond vibrations, radiofrequency in a magnetic field flips nuclear spins, and mass spectrometry weighs the ions the molecule breaks into. Together they give the four questions a chemist needs answered: how much is present (UV), which functional groups are present (IR), how the carbon-hydrogen skeleton is joined (NMR) and what the molecular mass and formula are (MS). The Indian Pharmacopoeia 2026 (10th edition) prescribes UV assays, specific absorbance limits and IR identity tests for a large number of monographs, and LC-MS/MS is the backbone of bioequivalence and impurity work in Indian industry. It is examined in Pharmaceutical Analysis and Pharmaceutical Chemistry papers, in GPAT and NIPER entrances, and in QC/QA/analytical-development interviews at Sun Pharma, Cipla, Dr Reddy's, Lupin, Zydus, Torrent, Aurobindo, Divi's, Syngene and the CROs.

Explained

Fundamentals common to all spectroscopy

UV-visible spectroscopy

Infrared spectroscopy

NMR spectroscopy

Mass spectrometry

Choosing and combining the techniques

Key points

Formulas and examples

A = log₁₀(I₀/I) = log₁₀(100/%T) = ε · b · c — A = absorbance (unitless), I₀ and I = incident and transmitted intensity, ε = molar absorptivity (L mol⁻¹ cm⁻¹), b = path length (cm), c = concentration (mol L⁻¹)
%T = (I/I₀) × 100; A = 2 − log₁₀(%T)
ε = A(1%, 1 cm) × M / 10 — M = molar mass (g mol⁻¹); A(1%, 1 cm) is for 1 g per 100 mL, 1 cm path
E = hc/λ = hcν̄; E (eV) = 1240/λ(nm); E (kJ mol⁻¹) = 1.196 × 10⁵ / λ(nm)
ν̄ (cm⁻¹) = (1/2πc)·√(k/µ), with µ = m₁m₂/(m₁+m₂) — k = force constant (N m⁻¹), µ = reduced mass (kg), c = 3 × 10¹⁰ cm s⁻¹
Number of fundamental vibrations = 3N − 6 (non-linear), 3N − 5 (linear)
ν (Larmor) = γB₀/2π; for ¹H, γ/2π = 42.577 MHz T⁻¹; for ¹³C, 10.705 MHz T⁻¹
δ (ppm) = [(ν_sample − ν_TMS) / ν_spectrometer] × 10⁶; peak separation Δν (Hz) = Δδ (ppm) × spectrometer frequency (MHz)
Double-bond equivalents, DBE = (2C + 2 + N − H − X)/2 — C, N, H, X = numbers of carbon, nitrogen, hydrogen, halogen atoms
m/z = mass/charge; Resolution R = m/Δm; M+1 (% of M) ≈ 1.1 × number of carbons

Example 1 — UV assay of paracetamol tablets (IP method, A(1%, 1 cm) = 715 at 257 nm in 0.1 M NaOH). Powdered tablet equivalent to 100 mg (label claim) is dissolved and made up to 100 mL; 1.0 mL of this is diluted to 100 mL. Measured A = 0.701 in a 1 cm cell.

  1. c (in the measured solution) = A / [A(1%, 1 cm) × b] = 0.701 / 715 = 9.804 × 10⁻⁴ g per 100 mL = 9.804 µg mL⁻¹.
  2. Undo the 1 → 100 dilution: 9.804 × 100 = 980.4 µg mL⁻¹ = 0.9804 mg mL⁻¹.
  3. Content in the 100 mL stock = 0.9804 × 100 = 98.04 mg.
  4. Percentage of label claim = 98.04/100 × 100 = 98.0% — inside the IP limit of 95.0–105.0% for paracetamol tablets.

Note A = 0.701 lies in the 0.2–0.8 window, so the dilution scheme is sound.

Example 2 — converting specific absorbance to molar absorptivity, and the photon energy. Paracetamol, M = 151.16 g mol⁻¹, A(1%, 1 cm) = 715 at 257 nm.

Example 3 — IR: Hooke's law and DBE for paracetamol (C₈H₉NO₂, M = 151). Force constant of a C−H single bond k ≈ 500 N m⁻¹.

  1. µ = (12 × 1)/(12 + 1) = 0.923 amu = 0.923 × 1.6605 × 10⁻²⁷ = 1.533 × 10⁻²⁷ kg.
  2. √(k/µ) = √(500 / 1.533 × 10⁻²⁷) = √(3.262 × 10²⁹) = 5.711 × 10¹⁴ s⁻¹.
  3. ν̄ = 5.711 × 10¹⁴ / (2π × 3 × 10¹⁰) = 5.711 × 10¹⁴ / 1.885 × 10¹¹ = 3029 cm⁻¹ — matching the observed aromatic/aliphatic C−H stretch near 3000 cm⁻¹.
  4. DBE = (2×8 + 2 + 1 − 9)/2 = 10/2 = 5 → one benzene ring (4) plus one C=O (1).
  5. Expected bands: 3330 (phenolic O−H, broad), 3160 (amide N−H), 1650 (amide C=O, lowered by conjugation and resonance), 1610 and 1510 (aromatic C=C), 1240 (C−O), 835 cm⁻¹ (para-disubstituted ring, two adjacent H).

Example 4 — NMR: field, frequency and reading a spectrum of benzocaine (ethyl 4-aminobenzoate, C₉H₁₁NO₂).

  1. Field needed for a 400 MHz ¹H instrument: B₀ = 400 / 42.577 = 9.395 T. On the same magnet ¹³C resonates at 10.705 × 9.395 = 100.6 MHz.
  2. Two aromatic signals at δ 7.85 and 6.64 are Δδ = 1.21 ppm apart = 1.21 × 400 = 484 Hz on this instrument, but only 1.21 × 100 = 121 Hz on a 100 MHz instrument — the shift in ppm is unchanged, the separation in Hz is not.
  3. Spectrum: δ 7.85 (d, J = 8.6 Hz, 2H, ortho to C=O), 6.64 (d, J = 8.6 Hz, 2H, ortho to NH₂ — shielded by the electron-donating amine), 4.30 (q, J = 7.1 Hz, 2H, OCH₂), 4.05 (br s, 2H, NH₂ — vanishes on a D₂O shake), 1.36 (t, J = 7.1 Hz, 3H, CH₃).
  4. Integration total = 2+2+2+2+3 = 11 H, exactly the hydrogen count of C₉H₁₁NO₂. DBE = (18 + 2 + 1 − 11)/2 = 5 → ring (4) + ester C=O (1).
  5. The quartet/triplet pair with identical J = 7.1 Hz is the signature ethyl group; the two aromatic doublets with J ≈ 8.6 Hz confirm para substitution.

Example 5 — mass spectrum of paracetamol (EI).

m/zAssignmentReasoning
151M⁺˙Nominal mass odd → odd number of N; paracetamol has one N (nitrogen rule satisfied)
152M+18 carbons → ≈ 8 × 1.1 = 8.8% of the M peak intensity
109M − 42Loss of neutral ketene, CH₂=C=O, from the acetamido group; usually the base peak
80109 − 29Further loss of CHO/HCN-type fragment from the ring
43CH₃CO⁺Acylium ion from α-cleavage of the amide

No M+2 of about 33% or 100% is present, so no chlorine or bromine. If an unknown instead showed M at 1.0 and M+2 at 0.33 relative intensity, one chlorine is present; 1.0 : 1.0 means one bromine.

FeatureUV-visibleIRNMRMass
What is excitedValence electronsBond vibrationsNuclear spinMolecule is ionised and fragmented
Region / unit200–800 nm4000–400 cm⁻¹MHz radiofrequencym/z
Main informationConjugation, λmax, concentrationFunctional groups, polymorphsSkeleton, connectivity, stereochemistryMolecular mass, formula, fragments
Quantitative?Yes, the standard assay toolSemi-quantitativeYes (qNMR), less commonYes, best for trace levels
SampleDilute solution, quartz cellKBr pellet, mull, film, ATRmg in deuterated solventµg or less, destroyed
Sensitivityµg mL⁻¹µg–mgmg (least sensitive)pg–ng (most sensitive)
Typical Indian useIP assay, dissolution testingIP identity testStructure proof, reference standardsBioequivalence, nitrosamine testing

Where it is used

Interview questions

Common mistakes

Related topics

Chromatography: HPLC, GC and TLC · Pharmaceutical analysis: titrimetric and instrumental methods · Medicinal chemistry: drug classes and SAR · Analytical method validation and ICH Q2(R2) · Impurity profiling and stability studies · Good laboratory practice and data integrity.

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