Knowledge / Chemistry / Alcohols, phenols and ethers

Alcohols, phenols and ethers

Chemistry (B.Sc) · Organic chemistry · free study notes for exams, placements and interviews

In short

Alcohols (R-OH), phenols (Ar-OH) and ethers (R-O-R') are the three families of oxygen-containing organic compounds in which oxygen is singly bonded. They are the gateway functional groups of organic chemistry: alcohols link hydrocarbons to aldehydes, ketones and acids; phenols show how an aromatic ring changes the chemistry of the same -OH group; ethers are the standard solvents (diethyl ether, THF) in which most synthesis is done. B.Sc papers, CSIR-UGC NET/JRF, GATE Chemistry (CY), IIT-JAM and placement tests for pharma, agrochemical, dyes and specialty-chemical firms examine this topic heavily, usually as distinguishing tests, named reactions and acidity ordering. Industrially these are ethanol (sugar/molasses distilleries), phenol and cumene (petrochemical), glycerol (oleochemical) and polyether/epoxy intermediates.

Explained

Structure, classification and nomenclature essentials

Physical properties and hydrogen bonding

Acidity and basicity

Preparation

Alcohols:

  1. Hydration of alkenes - acid-catalysed, Markovnikov, via carbocation (rearrangement possible).
  2. Hydroboration-oxidation (B₂H₆ then H₂O₂/OH⁻) - anti-Markovnikov, *syn* addition, no rearrangement.
  3. Oxymercuration-demercuration - Markovnikov without rearrangement.
  4. Reduction of carbonyls: NaBH₄ (selective, aldehydes/ketones), LiAlH₄ (also esters, acids, amides), catalytic H₂/Ni.
  5. Grignard route: RMgX + HCHO → 1°; + other aldehyde → 2°; + ketone → 3°; + ester (2 eq) → 3°; + epoxide → alcohol two carbons longer.
  6. Hydrolysis of haloalkanes (aq. KOH) and fermentation of sugars (industrial ethanol: C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂ by zymase).

Phenols:

  1. Cumene process (dominant industrial route): benzene + propene → cumene; air oxidation → cumene hydroperoxide; acid cleavage → phenol + acetone.
  2. From chlorobenzene (Dow process, NaOH, 350 °C/high pressure); from benzenesulphonic acid (fused NaOH); from diazonium salts (warm water); from aniline via diazotisation.

Ethers:

  1. Williamson synthesis: R-X + R'O⁻Na⁺ → R-O-R' (Sₙ2). Use the less hindered alkyl halide and the more hindered alkoxide; 3° halides give alkene by E2 instead. Aryl ethers (anisole) come from ArO⁻ + CH₃I, never ArX + RO⁻.
  2. Acid dehydration of alcohols - good for symmetrical 1° ethers (ethanol/H₂SO₄ at 413 K → diethyl ether; at 443 K → ethene).
  3. Epoxides from alkene + peroxyacid, or from halohydrin + base.

Reactions of alcohols

Reactions of phenols

Reactions of ethers and epoxides

Industrial and Indian regulatory context

Key points

Formulas and examples

Degree of unsaturation (for CₙH_mO_x): DoU = (2n + 2 − m)/2 - oxygen is ignored; each ring or double bond counts 1.
Alcohol/ether general formula: CₙH₂ₙ₊₂O (saturated, acyclic, one oxygen) - alcohols and ethers of the same n are functional isomers.
Ka = [H⁺][A⁻]/[HA]; pKa = −log Ka; for a weak acid of concentration c, [H⁺] ≈ √(Ka·c) and pH = −log[H⁺].
Henderson-Hasselbalch: pH = pKa + log([A⁻]/[HA]) - used for phenol/phenoxide buffers.
% ionisation α = [A⁻]/c × 100; for a weak acid α ≈ √(Ka/c) × 100.
Zeisel estimation: % OCH₃ = (mass of AgI × 31.03 / (234.77 × mass of sample)) × 100, where 31.03 g/mol = OCH₃ and 234.77 g/mol = AgI.
Fermentation stoichiometry: C₆H₁₂O₆ → 2 C₂H₅OH + 2 CO₂; theoretical yield = 2 × 46.07/180.16 = 0.5114 g ethanol per g glucose (51.14%).

Example 1 - pH of a phenol solution. Find the pH of 0.100 M phenol, Ka = 1.0 × 10⁻¹⁰.

Example 2 - ethanol yield from molasses. A distillery processes 100 tonnes/day of molasses containing 45% fermentable sugars; fermentation efficiency is 90% of theory and distillation recovery 96%.

Example 3 - Zeisel methoxyl determination. 0.2500 g of a methylated sugar gave 0.4700 g of AgI.

Example 4 - structure from formula and tests. A compound C₄H₁₀O is optically active, gives H₂ with Na, turns turbid with Lucas reagent in about five minutes and gives a positive iodoform test.

Example 5 - Williamson planning. To make *tert*-butyl methyl ether (MTBE):

PropertyAlcohol (ethanol)PhenolEther (diethyl ether)
O attached tosp³ Csp² aromatic Ctwo C, no O-H
pKa≈ 16≈ 10.0not acidic
Soluble in NaOHNoYesNo
FeCl₃ colourNoneVioletNone
Na metal, H₂ gasYesYesNo
OxidationTo aldehyde/ketone/acidTo quinoneResistant (forms peroxides in air)
Typical cleavageC-O broken by HX, SOCl₂Ar-O very strong, not cleavedOnly hot HI/HBr
Boiling point78 °C182 °C34.6 °C
TestReagentResult distinguishes
LucasZnCl₂ + conc. HCl3° (instant) / 2° (~5 min) / 1° (heat)
Victor MeyerHNO₂ route, then alkalired 1°, blue 2°, colourless 3°
FeCl₃neutral FeCl₃phenol/enol violet-green
IodoformI₂ + NaOHmethyl carbinols and ethanol
NaHCO₃sat. NaHCO₃acid effervesces, phenol does not
PeriodateHIO₄vicinal diols cleaved

Where it is used

Interview questions

Common mistakes

Related topics

Organic reaction mechanisms · Aldehydes and ketones · Carboxylic acids and derivatives · Hydrocarbons · Stereochemistry · Organic nomenclature and isomerism

Open in the Knowledge reader →Find jobs →