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Chemical kinetics and catalysis

Chemistry (B.Sc) · Physical chemistry · free study notes for exams, placements and interviews

In short

Chemical kinetics studies how fast reactions go, what controls that speed, and what sequence of elementary steps the overall equation hides. Thermodynamics says whether a reaction can happen; kinetics says whether it will happen in a useful time, which is why reactor design, drug shelf-life and catalyst selection all rest on rate data. Catalysis is the industrial lever on rate: it lowers activation energy without being consumed, and over 90% of large-scale chemical processes use a catalyst. The topic carries heavy weight in B.Sc and M.Sc physical chemistry papers, in GATE Chemistry (XL/CY) and CSIR-UGC NET, and in technical interviews at pharma (Sun, Cipla, Dr Reddy's, Divi's), petrochemical (Reliance, IOCL, HPCL), fertiliser (IFFCO, RCF) and catalyst (Johnson Matthey India, Süd-Chemie/Clariant) employers.

Explained

Rate of reaction, rate laws, order and molecularity

Integrated rate equations and half-lives

Temperature dependence, activation energy and theories of reaction rate

Catalysis: principles and types

Experimental methods and Indian practice

Key points

Formulas and examples

Rate = −(1/a)d[A]/dt = (1/c)d[C]/dt — unit mol L⁻¹ s⁻¹
Rate = k[A]m[B]n; overall order n = m + n (n = overall order); units of k = (mol L⁻¹)1−n s⁻¹
Zero order: [A] = [A]₀ − kt; t½ = [A]₀/2k
First order: k = (2.303/t)·log([A]₀/[A]); t½ = 0.693/k (k in s⁻¹)
Second order (equal): 1/[A] = 1/[A]₀ + kt; t½ = 1/(k[A]₀); k in L mol⁻¹ s⁻¹
nth order: t½ = (2n−1 − 1)/[(n−1)k[A]₀n−1]
Arrhenius: k = A·e−Ea/RT; log(k₂/k₁) = (Ea/2.303R)·(T₂−T₁)/(T₁T₂); R = 8.314 J K⁻¹ mol⁻¹
Collision theory: k = P·Z·e−Ea/RT; Z = collision number (collisions L⁻¹ s⁻¹)
Eyring: k = (k_BT/h)·e−ΔG‡/RT; k_B = 1.381×10⁻²³ J K⁻¹, h = 6.626×10⁻³⁴ J s
Michaelis–Menten: v = v_max[S]/(K_M + [S]); Lineweaver–Burk: 1/v = (K_M/v_max)(1/[S]) + 1/v_max
First-order half-life from titre (sucrose/ester): k = (2.303/t)·log[(r₀ − r∞)/(r_t − r∞)]

Example 1 — first-order rate constant and completion time. The first-order decomposition of N₂O₅ has k = 6.93 × 10⁻⁴ s⁻¹ at 318 K.

Example 2 — order from initial-rate data. For 2NO + O₂ → 2NO₂:

Run[NO] mol L⁻¹[O₂] mol L⁻¹Initial rate mol L⁻¹ s⁻¹
10.100.102.5 × 10⁻³
20.200.101.0 × 10⁻²
30.100.205.0 × 10⁻³

Example 3 — activation energy from two temperatures. k = 2.0 × 10⁻³ s⁻¹ at 300 K and 1.6 × 10⁻² s⁻¹ at 330 K.

Example 4 — effect of a catalyst at constant temperature. A reaction with Ea = 100 kJ mol⁻¹ at 500 K is catalysed so that Ea falls to 75 kJ mol⁻¹ (A unchanged).

Example 5 — Michaelis–Menten. An enzyme shows v_max = 2.4 × 10⁻⁵ mol L⁻¹ s⁻¹ and K_M = 5.0 × 10⁻⁴ mol L⁻¹.

FeatureZero orderFirst orderSecond order
Rate lawkk[A]k[A]²
Linear plot[A] vs tln[A] vs t1/[A] vs t
Units of kmol L⁻¹ s⁻¹s⁻¹L mol⁻¹ s⁻¹
t½[A]₀/2k0.693/k1/(k[A]₀)
t½ vs [A]₀∝ [A]₀independent∝ 1/[A]₀
ExampleNH₃ on hot W; photochemicalN₂O₅ decomposition, radioactive decay2NO₂ → 2NO + O₂; saponification
FeatureHomogeneousHeterogeneousEnzymatic
PhaseSame as reactantsSeparate (usually solid)Aqueous, colloidal protein
SelectivityHighModerateExtremely high
ConditionsMildOften high T, p25–40 °C, narrow pH
SeparationDifficultEasy (filtration/fixed bed)Immobilisation needed
ExampleH⁺ in ester hydrolysis; oxo processFe in Haber, V₂O₅ in ContactUrease, invertase, amylase

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Related topics

Chemical thermodynamics · Surface chemistry and colloids · Chemical and ionic equilibrium · Electrochemistry (electrode kinetics and overpotential) · Photochemistry and radioactivity · Reaction mechanisms in organic chemistry

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