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s, p, d and f block elements

Chemistry (B.Sc) · Inorganic chemistry · free study notes for exams, placements and interviews

In short

The long form of the periodic table is divided into four blocks by the sub-shell that receives the last electron: s (groups 1-2 and He), p (groups 13-18), d (groups 3-12, the transition elements) and f (the lanthanoids and actinoids). Block position fixes valence-shell configuration, and that in turn fixes oxidation states, bonding type, colour, magnetism, acid-base and redox behaviour of every element and its compounds. This is the largest single scoring area of B.Sc inorganic chemistry and of CSIR-UGC NET, GATE Chemistry (CY), IIT-JAM and the technical rounds of Indian chemical, metallurgical, fertiliser, pharma and atomic-energy employers. Industrially it is the chemistry behind chlor-alkali and soda ash, aluminium and steel, sulphuric acid and fertilisers, pigments and catalysts, and India's rare-earth and thorium programme built on Kerala and Odisha beach sands.

Explained

How the blocks are defined and filled

s-block: alkali and alkaline earth metals

p-block: groups 13 to 18

d-block: the transition elements

f-block: lanthanoids and actinoids

Anomalies, trends and the exam favourites

Indian extraction, regulation and practice

Key points

Formulas and examples

Zeff = Z − S (Slater's rules: same-group ns/np electrons 0.35 each, (n−1) shell 0.85 each, (n−2) and inner 1.00 each; for d and f electrons all inner electrons count 1.00)
Spin-only magnetic moment: μ = √(n(n+2)) BM, n = number of unpaired electrons; 1 BM = 9.274 × 10⁻²⁴ J T⁻¹
L-S coupled moment (lanthanoids): μ = g√(J(J+1)) BM, with g = 1 + [J(J+1) + S(S+1) − L(L+1)] / [2J(J+1)]
Born-Haber: ΔfH°(MX) = ΔsubH(M) + IE(M) + ½D(X₂) + ΔegH(X) + U(lattice)
Born-Landé: U = −(N_A·M·z⁺·z⁻·e²)/(4πε₀·r₀) × (1 − 1/n), M = Madelung constant, r₀ = interionic distance (m), n = Born exponent
Polarising power ∝ (cation charge)/(cation radius)²; Fajans' rules follow from it
Faraday's law: mass m = (Q/F) × (M/z), Q in coulomb, F = 96,485 C mol⁻¹, M in g mol⁻¹, z = electrons per ion
Equivalent mass: KMnO₄ = M/5 (acid medium), K₂Cr₂O₇ = M/6; normality N = z × molarity

1. Lattice enthalpy of NaCl by the Born-Haber cycle. Data (kJ mol⁻¹): ΔfH°(NaCl) = −411, ΔsubH(Na) = +108, IE(Na) = +496, D(Cl₂) = +242, ΔegH(Cl) = −349.

2. Spin-only moments across 3d. Count unpaired d electrons, then μ = √(n(n+2)).

Iond-confignμ calc (BM)μ observed (BM)
Ti³⁺d¹11.731.75
V³⁺d²22.832.8
Cr³⁺d³33.873.8
Mn²⁺/Fe³⁺d⁵55.925.9
Co²⁺d⁷33.874.8-5.2 (orbital contribution)
Ni²⁺d⁸22.832.8-3.5
Cu²⁺d⁹11.731.9
Zn²⁺d¹⁰00diamagnetic

3. Why the spin-only formula fails for lanthanoids - Nd³⁺ (4f³, ground term ⁴I₉/₂). S = 3/2, L = 6, J = 9/2.

4. Energy to win 1 tonne of aluminium (Hall-Héroult). Al³⁺ + 3e⁻ → Al, so z = 3.

5. Dichromate titration of a ferrous salt. 20.0 mL of 0.02 M K₂Cr₂O₇ exactly oxidises 25.0 mL of Mohr's salt solution. Cr₂O₇²⁻ + 14H⁺ + 6Fe²⁺ → 2Cr³⁺ + 6Fe³⁺ + 7H₂O.

6. Zeff on the 3s electron of Na (Slater). Config 1s² 2s²2p⁶ 3s¹. Same shell: none. (n−1) = 8 electrons × 0.85 = 6.80. (n−2) = 2 × 1.00 = 2.00. S = 8.80 → Zeff = 11 − 8.80 = 2.20, which is why the 3s electron is lost so easily.

FeatureLanthanoids (4f)Actinoids (5f)
Common oxidation state+3 almost always+3 to +7 (U +6, Np +7)
RadioactivityOnly PmAll members
f-orbital shieldingWell shielded, 4f buriedLess shielded, 5f extended
ContractionLanthanoid contraction, regularActinoid contraction, larger
SpectraSharp, line-like f-f bandsBroader bands
ComplexesWeak, mostly ionic, high CNStronger, more covalent

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