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Process design and optimisation

Chemical Engineering (B.E./B.Tech) · Process control and design · free study notes for exams, placements and interviews

In short

Process design converts a product requirement into a complete, buildable and profitable plant: a flowsheet, mass and energy balances, equipment duties and sizes, utilities, an estimate of capital and operating cost, and a profitability number. Optimisation is the quantitative half of it - choosing operating conditions, sizes and structures that minimise total annual cost or maximise net present value, subject to balance, equilibrium, safety and statutory constraints. Almost every design decision is a trade-off between capital cost and operating cost, and the examinable skill is writing that trade-off as an objective function and finding its optimum. It is a heavily weighted GATE (CH) section ("Plant Design and Economics") and the core of the design project in every B.E./B.Tech chemical curriculum. Design, techno-economics and simulation roles at EIL, Technip Energies, L&T Hydrocarbon, Toyo, Jacobs, Tata Consulting Engineers, Reliance, IOCL/BPCL/HPCL, UPL and Aarti Industries interview directly on this material.

Explained

What process design covers, and in what order

Flowsheet synthesis and degrees of freedom

Capital cost estimation

Operating cost and profitability

Optimisation: formulation and methods

Classic design trade-offs worth memorising

Indian statutory and practice context

Key points

Formulas and examples

Capacity scaling: C₂ = C₁ (Q₂/Q₁)ⁿ - C = cost (Rs), Q = capacity or size (any consistent unit), n = exponent (≈0.6 typical)
Index escalation: C_now = C_then × (I_now / I_then) - I = cost index (dimensionless)
Lang factor: FCI = f_L × Σ C_e - C_e = purchased equipment cost (Rs); f_L ≈ 4.74 (fluid), 3.63 (solid-fluid), 3.10 (solid)
Total capital investment: TCI = FCI + working capital (+ land, start-up)
Factored manufacturing cost (Turton): COM ≈ 0.280 FCI + 2.73 C_OL + 1.23 (C_UT + C_WT + C_RM) - C_OL = operating labour, C_UT = utilities, C_WT = waste treatment, C_RM = raw materials (all Rs/yr)
Straight-line depreciation: D = (FCI − S)/n - S = salvage value, n = life (years)
Capital recovery factor: CRF = i(1+i)ⁿ / [(1+i)ⁿ − 1]; annualised capital charge = CRF × FCI (Rs/yr)
Present-value annuity factor: AF = [1 − (1+i)⁻ⁿ]/i - i = discount rate (fraction/yr)
NPV = Σ CF_t /(1+i)t − TCI; IRR = i at which NPV = 0
Simple payback = FCI / annual net cash flow (yr); ROI = annual net profit / TCI × 100
Total annual cost: TAC = CRF × FCI + annual operating cost (Rs/yr) - the usual design objective
Single-variable optimum: dTAC/dx = 0, d²TAC/dx² > 0; for TAC = a/x + bx, x_opt = √(a/b) and the two cost terms are equal at the optimum
Optimum reflux: R_opt ≈ (1.1 to 1.3) R_min; R_min from Underwood
Economic pipe diameter correlations have the form d_opt = k Gp ρ−q (G = mass flow kg/s, ρ = kg/m³); the constants depend on material and the cost data used, so use the correlation given in the question

Example 1 - scaling and escalation. A 50 m² stainless shell-and-tube exchanger cost Rs 12.0 lakh when the plant cost index was 556.8. Estimate a 120 m² unit at an index of 800 (n = 0.6).

Example 2 - Lang factor and annualised capital. Purchased equipment for a solvent recovery plant totals Rs 8.0 crore (fluid processing, f_L = 4.74). Working capital 15% of FCI. Life 10 years, i = 12%.

Example 3 - profitability. FCI Rs 40 crore, net cash flow Rs 9 crore/yr for 10 years, discount rate 12%.

Example 4 - optimum insulation thickness (analytical optimum). For a steam line, annual heat-loss cost ≈ 7,200/x (Rs/yr, x in cm of insulation) and annualised insulation cost = 800x (Rs/yr).

Example 5 - linear programming (product mix). Products A and B give contributions of Rs 400/t and Rs 300/t. Reactor time: 2 h/t (A), 1 h/t (B), 100 h/week available. Separation: 1 h/t (A), 2 h/t (B), 80 h/week available.

CriterionDiscounts cash flow?StrengthWeakness
Payback periodNoSimple, shows liquidity riskIgnores life after payback, no time value
ROINoEasy from accountsDepends on depreciation convention
NPVYesAbsolute value added; correct rankingNeeds a discount rate; scale-dependent
IRR (DCFROR)YesRate comparable to cost of capitalCan be multiple/undefined; misranks unequal scales
Equivalent annual costYesCompares unequal livesNeeds life and salvage assumptions
MethodProblem typeFindsTypical use
Simplex (LP)LinearGlobal optimumBlending, product mix, utility dispatch
SQP / interior point (NLP)Smooth nonlinearLocal optimumFlowsheet and column optimisation
Branch and bound (MILP/MINLP)Discrete + continuousGlobal (MILP)Column sequence, HEN structure, unit selection
Golden section1 variable, unimodalLocal optimumQuick line search, lab data
Genetic algorithm / SANon-convex, black boxNear-globalMulti-objective, simulator-in-the-loop

Where it is used

Interview questions

Common mistakes

Related topics

Pinch analysis and energy integration · Process equipment design · Process flow diagrams and P&IDs · Mass transfer: distillation and absorption · Chemical reaction engineering: reactor design · Plant safety: HAZOP and PSM

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