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Inequalities

Placement essentials (aptitude, reasoning, verbal, communication, interviews, Excel, workplace) (All) · Logical reasoning · free study notes for exams, placements and interviews

In short

An inequality question gives relations between letters — such as P ≥ Q > R = S — and asks which stated conclusions must follow. The whole topic rests on one idea: a relation travels along a chain only while the arrows point the same way, and a single reversal breaks it. It appears in two dresses: direct inequalities using >, <, ≥, ≤, = and coded inequalities where symbols like @, #, $ stand for those relations. It is a guaranteed scoring block in IBPS, SBI, RBI, RRB, SSC, LIC and insurance exams, and in campus aptitude tests (TCS NQT, Infosys, Wipro, Capgemini, Accenture, Cognizant), because every question is solvable in under 30 seconds with certainty — unlike puzzles, there is no guesswork. The same logic drives eligibility rules in software: salary bands, cut-off marks, credit-score slabs and Excel IF conditions.

Explained

The symbols and what the words mean

Phrase in the questionSymbol
A is greater than BA > B
A is not greater than BA ≤ B
A is not smaller than BA ≥ B
A is neither greater than nor equal to BA < B
A is neither smaller than nor equal to BA > B
A is neither greater than nor smaller than BA = B
A is not equal to BA ≠ B

The chain rule — the only law you need

ChainValid conclusionReason
A > B > CA > Csame direction, both strict
A > B ≥ CA > Cone strict link makes it strict
A ≥ B > CA > Csame
A ≥ B ≥ CA ≥ Call weak
A ≥ B = CA ≥ C= transmits
A = B = CA = Cequality is transitive
A > B < Cnothingdirection reverses
A ≤ B ≥ Cnothingdirection reverses
A > B ≠ Cnothing≠ has no direction
A ≠ B ≠ CnothingA may equal C

Step-by-step method

  1. Decode every coded symbol into >, <, ≥, ≤, = beside the question — never reason in the codes.
  2. Merge the statements into a single chain on the common letters; if two chains share no letter, keep them separate (nothing can be concluded across them).
  3. Normalise direction so the chain reads one way (all > / ≥).
  4. For each conclusion, find the two letters and walk the path: unbroken and same-direction → it follows; otherwise it does not.
  5. If the derived relation is weak (A ≥ B) and the conclusion asks for strict (A > B) or for =, mark it *not definite* and go to the either-or check.
  6. Answer in the exam's option format: only I, only II, both, either, neither, all.

Either-or (complementary pairs) — definitely true vs possibly true

Coded inequalities

Filter / reverse questions and symbol-insertion

Algebraic inequalities (the companion quant block)

Key points

Formulas and examples

Transitivity (same direction): if A R₁ B and B R₂ C, where R₁, R₂ ∈ {>, ≥, =}, then A R C, where R = ">" if at least one of R₁, R₂ is ">", R = "≥" if at least one is "≥" and none is ">", and R = "=" only if both are "=".
No-conclusion rule: if the path contains one relation from {>, ≥} and one from {<, ≤} (or any ≠ with a directional sign), no relation between the end letters follows.
Either-or test: "either I or II" is true ⇔ (statements ⇒ I OR II) AND (statements ⇏ I) AND (statements ⇏ II).
Complementary pairs: (A > B, A ≤ B); (A ≥ B, A < B); (A = B, A ≠ B); (A > B, A = B) given A ≥ B.
Sign manipulation: a > b ⇒ a + k > b + k; a > b, k > 0 ⇒ ak > bk; a > b, k < 0 ⇒ ak < bk; a > b > 0 ⇒ 1/a < 1/b.
Modulus: |x| ≤ a ⇔ −a ≤ x ≤ a; |x| ≥ a ⇔ x ≤ −a or x ≥ a (a ≥ 0).

Example 1 — direct inequality with an either-or Statements: P ≥ Q > R = S ≤ T Conclusions: I. P > S II. T > R III. Either T > R or T = R IV. Q < T

Answer: I and III follow.

Example 2 — coded inequality Legend: X % Y = X ≥ Y; X @ Y = X > Y; X # Y = X < Y; X $ Y = X ≤ Y; X \* Y = X = Y. Statements: M @ N, N % O, O # P, P $ Q Decoded chain: M > N ≥ O < P ≤ Q

Answer: only I and II.

Example 3 — filter type (choose the expression) Which expression makes both "M > P" and "N ≥ Q" definitely true? (a) M > N ≥ P = Q (b) M ≥ N > P ≤ Q (c) M > N ≤ P ≥ Q (d) M = N ≥ P < Q

Answer: (a).

Example 4 — symbol insertion Fill the blanks so that A > E is definitely true: A ≥ B _ C _ D _ E

Answer: a set such as (>, =, ≥) — i.e. at least one strict sign, and no reversal.

Example 5 — possibility question and x-versus-y (i) Statements: A ≤ B < C = D ≥ E. Which is possibly true?

(ii) I. x² − 11x + 30 = 0 → (x − 5)(x − 6) = 0 → x = 5, 6. II. y² − 15y + 56 = 0 → (y − 7)(y − 8) = 0 → y = 7, 8. Every y-root exceeds every x-root → x < y. (iii) I. 2x² − 7x + 3 = 0 → (2x − 1)(x − 3) = 0 → x = 0.5, 3. II. y² − 5y + 6 = 0 → y = 2, 3. x = 3 > y = 2 but x = 0.5 < y = 2 → relation cannot be established.

Conclusion askedDerived relationVerdict
A > BA > Bfollows
A ≥ BA > Bfollows (> satisfies ≥)
A > BA ≥ Bnot definite → check either-or with A = B
A = BA ≥ Bnot definite
A ≠ BA > Bfollows
A < Bnothing derivabledoes not follow

Where it is used

Interview questions

Common mistakes

Related topics

Syllogisms · Statements and conclusions · Data sufficiency · Coding-decoding · Quadratic equations and quantity comparison · Seating arrangement and puzzles

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