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Friction, belts and screw jacks

Mechanical Engineering (B.E./B.Tech) · Engineering mechanics · free study notes for exams, placements and interviews

In short

Friction is the resistance that acts along the surface of contact when one body slides or tends to slide on another. Engineering mechanics treats it as a quantified force (F = μN) and then applies it to machines that depend on friction to work — screw jacks, wedges, belts, ropes, brakes, clutches and bearings. The topic is scoring in first-year Engineering Mechanics, reappears in Theory of Machines and Design of Machine Elements, and is a standing GATE/ESE item (ratio of tensions, maximum power, self-locking condition). Interviewers at Tata Motors, Mahindra, L&T, Thermax, Kirloskar, Elecon, Fenner, ABB, BHEL and every plant-maintenance role ask why a jack holds its load, why a V-belt grips better than a flat belt and why belt power peaks and then falls with speed.

Explained

Dry (Coulomb) friction: laws, angles and types

Bodies on planes, ladders and wedges

Power screws and the screw jack

Belt and rope drives: geometry and ratio of tensions

Power, centrifugal tension and maximum power

Pivot, collar, bearing and clutch friction

Standards, codes and Indian practice

Key points

Formulas and examples

F = μN; μ = tan φ; angle of repose θ_r = φ. F = limiting friction (N), N = normal reaction (N), μ dimensionless.
Up a plane: P = W(sin α + μ cos α) if P ∥ plane; P = W tan(α + φ) if P horizontal; P = W sin(α + φ)/cos(θ − φ) in general; P_min = W sin(α + φ) at θ = φ. Down/holding: replace φ by −φ.
Ladder (smooth wall, rough floor): tan θ ≥ 1/(2μ), θ = angle with floor.
Screw: tan α = l/(π d_m); T_raise = W(d_m/2)·(tan α + μ)/(1 − μ tan α); T_lower = W(d_m/2)·(μ − tan α)/(1 + μ tan α); P_handle = T/L (N·m, m).
η_screw = tan α/tan(α + φ) = W·l/(2πT); VR = 2πL/l; MA = W/P; η = MA/VR. Self-locking: φ ≥ α.
η_max = (1 − sin φ)/(1 + sin φ) at α = 45° − φ/2. Collar torque T_c = μ_c W R_c. V-thread: μ′ = μ/cos β.
Differential screw jack: VR = 2πL/(p₁ − p₂); compound: VR = 2πL/(p₁ + p₂).
Belt: v = πdN/60 (m/s); T₁/T₂ = eμθ (flat), eμθ/sin β (V); T_c = mv² (N, m in kg/m); T_max = σ·b·t; P = (T₁ − T₂)v (W); T₀ = (T₁ + T₂ + 2T_c)/2.
Maximum power: T_c = T_max/3, v_opt = √(T_max/3m), P_max = (2T_max/3)(1 − 1/eμθ)·v_opt.
Open belt: L = π(r₁ + r₂) + 2x + (r₁ − r₂)²/x; crossed: L = π(r₁ + r₂) + 2x + (r₁ + r₂)²/x.
sin α = (r₁ ∓ r₂)/x; θ_small = π − 2α (open), θ = π + 2α (crossed). N₂/N₁ = (d₁ + t)/(d₂ + t)·(1 − s/100).
Clutch/collar: T = μW(R + r)/2 (uniform wear); T = (2/3)μW(R³ − r³)/(R² − r²) (uniform pressure); × number of friction pairs.

Example 1 — block on an inclined plane (all three cases). W = 500 N, α = 20°, μ = 0.3 → φ = tan⁻¹0.3 = 16.70°.

Example 2 — screw jack with collar friction. Single-start square thread, outside diameter 50 mm, pitch 10 mm, μ = 0.15 (φ = 8.53°), load W = 20 kN, handle length 600 mm, collar mean radius 40 mm, μ_c = 0.12.

  1. d_m = 50 − 10/2 = 45 mm; tan α = 10/(π × 45) = 0.07075 → α = 4.05°. Since φ = 8.53° > α, the jack is self-locking.
  2. Screw torque to raise = 20 000 × 0.0225 × (0.07075 + 0.15)/(1 − 0.15 × 0.07075) = 450 × 0.22311 = 100.4 N·m.
  3. Screw efficiency η = 0.07075/0.22311 = 31.7% (check: W·l/2πT = 20 000 × 0.010/(2π × 100.4) = 0.317 ✓).
  4. Torque to lower = 450 × tan(8.53° − 4.05°) = 450 × 0.07843 = 35.3 N·m — positive, confirming self-locking.
  5. Collar torque = 0.12 × 20 000 × 0.040 = 96 N·m. Total = 196.4 N·m → effort at handle P = 196.4/0.6 = 327 N.
  6. Overall efficiency = 20 000 × 0.010/(2π × 196.4) = 16.2%. VR = 2π × 600/10 = 377; MA = 20 000/327 = 61.2.
  7. Best possible efficiency for this thread friction = (1 − sin 8.53°)/(1 + sin 8.53°) = 0.8517/1.1483 = 74.2% at α = 40.7° — but such a lead would not be self-locking, so a jack deliberately sacrifices it.

Example 3 — flat belt power and maximum power. Belt 100 mm × 8 mm, density 1 000 kg/m³, permissible stress 2.5 MPa; pulley 400 mm at 600 rpm; μ = 0.3, angle of lap 165°.

  1. v = π × 0.4 × 600/60 = 12.57 m/s; m = 1 000 × 0.1 × 0.008 = 0.8 kg/m.
  2. T_max = 2.5 × 10⁶ × 0.1 × 0.008 = 2 000 N; T_c = 0.8 × 12.57² = 126.3 N; T₁ = 2 000 − 126.3 = 1 873.7 N.
  3. θ = 165° = 2.880 rad; μθ = 0.864; e0.864 = 2.373 → T₂ = 1 873.7/2.373 = 789.8 N.
  4. P = (1 873.7 − 789.8) × 12.57 = 13.6 kW. Initial tension T₀ = (1 873.7 + 789.8 + 252.6)/2 = 1 458 N.
  5. Maximum-power speed v = √(2 000/(3 × 0.8)) = 28.87 m/s (≈ 1 379 rpm on this pulley), where T_c = 666.7, T₁ = 1 333.3, T₂ = 562.0 → P_max = 771.3 × 28.87 = 22.3 kW. The drive is running well below its optimum speed.

Example 4 — why a V-belt grips better. Groove half-angle β = 19°, μ = 0.25, θ = 160° = 2.793 rad.

Example 5 — belt length, lap angle and velocity ratio. d₁ = 600 mm, d₂ = 300 mm, centre distance x = 1.5 m, N₁ = 500 rpm.

  1. Open belt: sin α = (0.30 − 0.15)/1.5 = 0.1 → α = 5.74°; θ_small = 180° − 11.48° = 168.5° (2.941 rad), θ_large = 191.5°.
  2. L_open = π(0.45) + 2(1.5) + (0.15)²/1.5 = 1.414 + 3 + 0.015 = 4.43 m.
  3. Crossed belt: α = sin⁻¹(0.45/1.5) = 17.46° → θ = 214.9°; L = 1.414 + 3 + 0.2025/1.5 = 4.55 m (longer, and both pulleys get the larger lap).
  4. Ideal N₂ = 500 × 600/300 = 1 000 rpm. With belt thickness 5 mm and 3% total slip: N₂ = 500 × (605/305) × 0.97 = 962 rpm — a 3.8% shortfall, which is why belts are not used where the ratio must be exact.
DriveGrip basisRatio exact?Centre distanceTypical use
Flat beltμθ frictionNo (slip + creep)LargeOld line shafts, conveyors, flat-belt live rolls
V-beltμθ/sin β wedgeNo (small slip)Short to mediumPumps, compressors, fans, machine tools, agri equipment
Timing beltTooth engagementYesShortCamshaft drives, printers, CNC axes
ChainTooth engagementYesMediumTwo-wheelers, cement and sugar plant drives
GearTooth engagementYesVery shortGearboxes, reducers

Where it is used

Interview questions

Common mistakes

Related topics

Engineering mechanics: statics and dynamics · Design of machine elements: power screws, bolted joints and springs · Theory of machines: brakes, clutches, dynamometers and flywheels · Gears, chains and drive selection · Tribology, lubrication and bearings · Strength of materials: stress, strain and factor of safety

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