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Enzyme technology

Biotechnology Engineering (B.E./B.Tech) · Bioprocess engineering · free study notes for exams, placements and interviews

In short

Enzyme technology is the use of enzymes - protein (and some RNA) catalysts - as industrial catalysts, together with the engineering needed to measure, stabilise, immobilise and operate them in reactors. Enzymes give enormous rate enhancement with high substrate, regio- and stereo-specificity at mild temperature, near-neutral pH and atmospheric pressure, so they replace harsh chemical steps and reduce effluent load. The examinable core is kinetics (Michaelis-Menten, inhibition, linearisation), immobilization with diffusional limitation, deactivation kinetics and enzyme reactor design - a standing section of GATE Biotechnology (BT) and of university Bioprocess Engineering papers. Indian employers who test it directly include Advanced Enzyme Technologies, Novozymes South Asia, Biocon, Syngene, Dr Reddy's, Zydus, Aurobindo, Hindustan Unilever (detergents), Amul and the starch and textile processors of Gujarat, Punjab and Tirupur.

Explained

What enzymes are, how they catalyse, and how they are classified

Michaelis-Menten kinetics and its linear forms

Inhibition, activation and deactivation

Enzyme sources, production and recovery (enzyme-specific points)

Immobilization and diffusional limitation

Enzyme reactors and their design equations

Indian practice, regulation and safety

Key points

Formulas and examples

v = V_max·[S] / (K_m + [S]) — Michaelis-Menten rate; v, V_max in mol L⁻¹ s⁻¹ (or U/mL), [S] and K_m in mol/L
1/v = (K_m/V_max)(1/[S]) + 1/V_max — Lineweaver-Burk: slope K_m/V_max, y-intercept 1/V_max, x-intercept −1/K_m
v = V_max − K_m(v/[S]) — Eadie-Hofstee; [S]/v = (1/V_max)[S] + K_m/V_max — Hanes-Woolf
V_max = k_cat·[E]₀ ; k_cat = V_max/[E]₀ (s⁻¹) ; catalytic efficiency = k_cat/K_m (M⁻¹ s⁻¹)
Competitive: v = V_max[S]/(K_m(1+[I]/K_i) + [S]) ; Uncompetitive: v = V_max[S]/((K_m+[S])(1+[I]/K_i')) ; Non-competitive: v = V_max[S]/((K_m(1+[I]/K_i)) + [S](1+[I]/K_i'))
Substrate inhibition: v = V_max[S]/(K_m + [S] + [S]²/K_I) ; [S]_opt = √(K_m·K_I)
Hill: v = V_max[S]n/(K' + [S]n) ; n = Hill coefficient (dimensionless)
Specific activity = total activity (U) / total protein (mg) ; Purification fold = SA_step/SA_crude ; % yield = total activity_step/total activity_crude × 100
Deactivation: E(t) = E₀e−k_d t ; t₁/₂ = ln2/k_d ; k_d = A·e−E_d/RT (k_d in h⁻¹ or s⁻¹)
Batch / PFR with MM kinetics: V_max·t = K_m·ln(S₀/S) + (S₀ − S) (t = reaction or residence time)
CSTR with MM kinetics: τ = V/Q = (S₀ − S)(K_m + S)/(V_max·S)
Thiele modulus (sphere, first-order regime): Φ = (R/3)·√(V_max/(K_m·D_e)) ; η = (1/Φ)[1/tanh(3Φ) − 1/(3Φ)]
External: Da = V_max/(k_L·a·S_b) ; observed rate = k_L·a·(S_b − S_s) at steady state
Conversion X = (S₀ − S)/S₀ ; Enzyme productivity = kg product per kg enzyme over its life

Example 1 - K_m and V_max from two points by Lineweaver-Burk. An amylase assay gives v = 0.25 µmol/min at [S] = 1 mM and v = 0.769 µmol/min at [S] = 10 mM.

Example 2 - activity balance for a purification step. Crude extract: 500 mL, 4 U/mL, 12 mg protein/mL. After ion exchange: 40 mL, 30 U/mL, 0.5 mg protein/mL.

Example 3 - thermal deactivation and replacement interval. An immobilised lactase at 50 °C has k_d = 0.035 h⁻¹ (first order).

Example 4 - CSTR versus PFR volume for 90% conversion. S₀ = 100 mmol/L, K_m = 10 mmol/L, V_max = 20 mmol L⁻¹ h⁻¹, feed Q = 2 L/h, X = 0.90 so S = 10 mmol/L.

Example 5 - internal diffusion in a bead. Spherical bead R = 0.5 mm = 5×10⁻⁴ m, V_max = 0.1 mol m⁻³ s⁻¹, K_m = 10 mol/m³, D_e = 5×10⁻¹⁰ m²/s, bulk [S] ≪ K_m (first-order regime).

ReactorOperates atVolume for high XBest forMain limitation
Batch STRFalling [S] with timeSmallSmall volumes, multiproductEnzyme lost each batch; downtime
CSTR (beads)Outlet [S]LargestSubstrate-inhibited, viscous feedsLow rate at high X; bead attrition
PFR / packed bedGradient S₀→SSmallestIsomerisation, hydrolysis at scaleΔP, channelling, no pH control
Fluidised bedNear-mixedIntermediateParticulate or gassy feedsExpansion control, abrasion
Membrane (hollow fibre)Near-mixed, product removedIntermediateProduct-inhibited reactionsFouling, polarisation
Inhibition typeK_m,appV_max,appLineweaver-Burk lines
Competitive↑ ×(1+[I]/K_i)unchangedMeet on 1/v axis
Uncompetitive↓ ×1/(1+[I]/K_i')↓Parallel
Non-competitive (pure)unchanged↓Meet on 1/[S] axis
Mixed↑ or ↓↓Meet in second/third quadrant

Where it is used

Interview questions

Common mistakes

Related topics

Fermentation technology · Bioreactor design · Downstream processing · Microbial biochemistry and metabolic pathways · Biochemical reaction engineering and kinetics · Biosensors and enzyme-based diagnostics

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