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Open channel flow

Civil Engineering (B.E./B.Tech) · Water and environment · free study notes for exams, placements and interviews

In short

Open channel flow is the flow of liquid in a conduit with a free surface at atmospheric pressure - canals, rivers, storm drains, part-full sewers and flumes. It differs fundamentally from pipe flow because the depth itself is an unknown that adjusts with discharge, slope and boundary resistance, so gravity rather than pressure difference drives the motion. It is a high-weightage section in GATE Civil (Fluid Mechanics and Hydraulics), ESE, state PSC/AE/JE papers and university exams, and is daily working knowledge for irrigation and canal design (CWC, state irrigation departments, WAPCOS), urban drainage (AMRUT storm-water projects), hydropower waterways and consultancy design offices (L&T, AFCONS, Tata Consulting Engineers).

Explained

Classification and basic geometry

Uniform flow and resistance equations

Most economical (efficient) section

Specific energy, critical flow and channel transitions

Gradually varied flow (GVF)

Rapidly varied flow - the hydraulic jump and measuring structures

Key points

Formulas and examples

Geometry: R = A/P; D = A/T; Z = A√D
Trapezoid, bed width b, depth y, side slope m horizontal to 1 vertical: A = (b + my)y; P = b + 2y√(1 + m²); T = b + 2my
Chezy: V = C√(R S) ; C in m½/s, R in m, S dimensionless
Manning: V = (1/n) R2/3 S1/2 ; Q = (1/n) A R2/3 S1/2 ; n in s/m1/3
Conveyance: K = (1/n) A R2/3, Q = K √S₀ ; Relation C = R1/6/n
Specific energy: E = y + Q²/(2gA²) ; Froude number: Fr = V/√(gD)
Critical flow: Q²T/(gA³) = 1 ; rectangular: yc = (q²/g)1/3, q = Q/B (m³/s per m), Emin = 1.5 yc
Specific force: M = A ȳ + Q²/(gA) ; ȳ = depth of centroid below surface
Jump (rectangular, horizontal): y₂/y₁ = ½(√(1 + 8Fr₁²) − 1) ; EL = (y₂ − y₁)³/(4 y₁ y₂) ; Lj ≈ 5-7 y₂
GVF: dy/dx = (S₀ − Sf)/(1 − Fr²) ; direct step: Δx = ΔE/(S₀ − S̄f) = (E₂ − E₁)/(S₀ − S̄f)
Wave celerity: c = √(g y) ; surge front absolute speed = V ± c
Weirs/flumes: broad-crested Q = 1.705 Cd b H3/2 ; V-notch Q = (8/15) Cd √(2g) tan(θ/2) H5/2

Example 1 - Uniform flow in a trapezoidal lined canal. A trapezoidal canal has bed width b = 6 m, side slopes 1.5H:1V, bed slope 1 in 2000, n = 0.016, depth of flow y = 2 m. Find Q and check the flow regime.

Example 2 - Critical depth and specific energy. A rectangular channel 5 m wide carries 20 m³/s at a depth of 2.0 m.

Example 3 - Hydraulic jump below a sluice gate. Water issues under a gate into a 4 m wide rectangular channel at y₁ = 0.4 m with Q = 16 m³/s.

Example 4 - Most economical rectangular section. Design the most economical rectangular concrete channel (n = 0.015) to carry 10 m³/s on a slope of 1 in 1000.

Example 5 - Direct step (one step of a backwater curve). A rectangular channel 6 m wide, n = 0.018, S₀ = 0.0004, carries Q = 12 m³/s. A weir raises the depth to 2.5 m. Find the distance to the section where depth is 2.4 m.

FeatureSubcritical (Fr < 1)Supercritical (Fr > 1)
Depth vs ycy > ycy < yc
VelocityV < √(gD)V > √(gD)
Disturbance travelBoth upstream and downstreamOnly downstream
Control sectionDownstreamUpstream
Typical occurrenceCanals, rivers in plainsBelow gates, chutes, steep spillway flow
Transition to the otherSmooth drawdownHydraulic jump (abrupt, lossy)
AspectUniform flowGVFRVF
Depth along lengthConstant (y₀)Varies slowlyChanges abruptly
Governing toolManning/Chezydy/dx equation, step methodsMomentum equation
PressureHydrostaticHydrostaticNon-hydrostatic
ExampleLong straight lined canalBackwater behind a barrageHydraulic jump, flow over a weir

Where it is used

Interview questions

Common mistakes

Related topics

Fluid properties and statics · Irrigation engineering · Dams and spillways · Flood control and river engineering · Sewer network design · Hydrology

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