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Dimensional analysis and similitude

Mechanical Engineering (B.E./B.Tech) · Fluid mechanics and machinery · free study notes for exams, placements and interviews

In short

Dimensional analysis groups the many physical variables of a flow problem into a few dimensionless numbers, so that an experiment on one model describes a whole family of real situations. Similitude is the set of conditions (geometric, kinematic and dynamic) that must hold for a scale model's readings to be transferable to the full-size prototype. It is the basis of every wind-tunnel, towing-tank and hydraulic-model test — spillways and ports at CWPRS Pune, ship hulls at NSTL Visakhapatnam, aerofoils at NAL Bengaluru, pump and turbine model acceptance tests at KBL, BHEL and Andritz. In exams it carries guaranteed marks in GATE/ESE (Buckingham pi, model laws, scale ratios) and in placement rounds it appears as "what is the Reynolds number and why does it matter".

Explained

Dimensions and dimensional homogeneity

Rayleigh's method and Buckingham's pi theorem

The important dimensionless numbers

Similitude: the three similarities

Model laws and when each is used

Distorted models, scale effects and Indian practice

Key points

Formulas and examples

Number of pi terms = n − m (n = variables, m = fundamental dimensions / rank)
Re = ρVL/μ = VL/ν · Fr = V/√(gL) · Ma = V/√(K/ρ) · Eu = V/√(Δp/ρ) · We = ρV²L/σ · St = fL/V
Drag: F = ρV²L²·φ(Re) → C_D = F/(½ρV²A)
Froude law (same fluid): Vr = Lr0.5, Tr = Lr0.5, ar = 1, Qr = Lr2.5, Force ratio = Lr³, Δp ratio = Lr, Power ratio = Lr3.5
Reynolds law: Vr = νr/Lr, Tr = Lr²/νr, Force ratio = ρr·νr²
Specific speed: Ns(pump) = N√Q/H3/4; Ns(turbine) = N√P/H5/4
QuantityDimensionSI unit
VelocityLT⁻¹m/s
Force / weightMLT⁻²N
Pressure, stressML⁻¹T⁻²Pa
Work, energy, torqueML²T⁻²J, N·m
PowerML²T⁻³W
Dynamic viscosity μML⁻¹T⁻¹Pa·s
Kinematic viscosity νL²T⁻¹m²/s
Surface tension σMT⁻²N/m
Discharge QL³T⁻¹m³/s
Bulk modulus KML⁻¹T⁻²Pa

Example 1 — Buckingham pi for drag. Drag F on a sphere depends on D, V, ρ, μ. n = 5, m = 3 → 2 pi terms. Repeating: ρ, V, D.

Example 2 — Rayleigh's method. Pressure-wave speed c = f(K, ρ): c = C·Kx·ρy → LT⁻¹ = (ML⁻¹T⁻²)x(ML⁻³)y. M: x + y = 0; T: −2x = −1 → x = ½, y = −½. So c = C√(K/ρ); experiment gives C = 1. For water (K = 2.07 GPa, ρ = 1000): c = √(2.07×10⁹/1000) ≈ 1,439 m/s.

Example 3 — Reynolds model law (oil pipeline). Prototype: D = 600 mm, V = 2 m/s, oil ν = 3.0×10⁻⁵ m²/s, ρ = 900 kg/m³. Model: D = 60 mm with water, ν = 1.0×10⁻⁶ m²/s, ρ = 1000 kg/m³.

Example 4 — Froude model law (spillway). A 1:36 model of a dam spillway; prototype design discharge 1,800 m³/s, design head 7.2 m. Lr = 1/36.

Example 5 — Ship resistance. Prototype ship 150 m long at 10 m/s in sea water (ρ = 1,025 kg/m³); 1:25 model in fresh water (ρ = 1,000).

Model lawDominant forceMatched numberTypical application
ReynoldsViscousRePipes, submarines, aerofoils, bearings
FroudeGravityFrSpillways, channels, ships, hydraulic jump
MachElasticMaSupersonic flight, compressors, water hammer
EulerPressureEu / σPressurised conduits, cavitation
WeberSurface tensionWeSprays, droplets, capillary flow

Where it is used

Interview questions

Common mistakes

Related topics

Viscous flow and pipe losses · Boundary layer, drag and lift · Fluid flow: Bernoulli and flow measurement · Hydraulic turbines · Centrifugal and reciprocating pumps · Compressible flow and gas dynamics

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