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Hydraulic turbines

Mechanical Engineering (B.E./B.Tech) · Fluid mechanics and machinery · free study notes for exams, placements and interviews

In short

A hydraulic turbine converts the energy of water falling through a head into shaft rotation, which an alternator turns into electricity. The three workhorses are the Pelton wheel (high head, low flow), the Francis turbine (medium head) and the Kaplan turbine (low head, large flow), chosen almost entirely by head and specific speed. India has roughly 47 GW of large hydro plus about 5 GW of small hydro and a growing pumped-storage fleet (CEA publishes the current figures monthly), run by NHPC, SJVN, THDC, NTPC and the state hydel corporations, with turbines made by BHEL Bhopal, Andritz, Voith and Flovel. The topic is heavily examined in GATE (ME and CE), in SSC-JE/state-PSU papers, and in interviews for BHEL, NHPC, NTPC, L&T, Jyoti and Kirloskar — usually through velocity triangles, efficiency, specific speed and cavitation.

Explained

The plant, the heads and the efficiencies

Classification

Impulse turbine: the Pelton wheel

Reaction turbines: Francis, Kaplan and variants

Draft tube, cavitation and runner setting

Specific speed, unit quantities, selection and performance curves

Governing, protection, codes and Indian practice

Key points

Formulas and examples

Net head: H = Hg − hf, where Hg = gross head (m), hf = total losses (m)
Water power: Pw = ρgQH (W); ρ = 1000 kg/m³, g = 9.81 m/s², Q in m³/s, H in m
Overall efficiency: ηo = P_shaft /(ρgQH) = ηh × ηv × ηm
Runner (peripheral) speed: u = πDN/60 (m/s); D = diameter (m), N = rpm; N = 120f/p
Euler turbine equation: work/unit weight = (Vw1u1 − Vw2u2)/g (m); runner power = ρQ(Vw1u1 − Vw2u2)
Pelton jet: V1 = Cv√(2gH); Q = (π/4)d²V1 per jet; d = jet diameter (m)
Pelton force and power: F = ρQ(V1 − u)(1 + k cos β2); P = F·u; ηh = 2(V1 − u)(1 + k cos β2)u / V1²
Maximum Pelton efficiency: at u = V1/2, ηh,max = (1 + k cos β2)/2; k = relative-velocity friction factor (0.85-1), β2 = bucket outlet angle = 180° − jet deflection angle (15° for a 165° bucket)
Pelton geometry: speed ratio φ = u/√(2gH); jet ratio m = D/d; buckets Z ≈ 15 + m/2
Francis flow: Q = πD1B1Vf1 × (vane thickness factor); B1 = runner width at inlet (m)
Inlet blade angle: tan θ1 = Vf1/(Vw1 − u1); outlet (no whirl): tan θ2 = Vf2/u2
Kaplan flow: Q = (π/4)(Do² − Dh²)Vf; Do = runner tip dia, Dh = hub (boss) dia (m)
Specific speed (metric): Ns = N√P/H1.25, with N in rpm, P in kW, H in m
Unit quantities: Nu = N/√H, Qu = Q/√H, Pu = P/H1.5
Thoma's cavitation factor: σ = (Ha − Hv − Hs)/H; Ha = atmospheric head (≈10.33 m at sea level, falling ≈0.11 m per 100 m altitude), Hv = vapour-pressure head, Hs = runner height above tailwater (m, negative if submerged)
Draft-tube efficiency: ηd = [(V2² − V3²)/2g − hf]/(V2²/2g); V2, V3 = inlet and outlet velocities

Example 1 - Pelton wheel, full design check. Net head H = 400 m, Q = 0.8 m³/s, Cv = 0.98, φ = 0.46, N = 500 rpm, bucket deflects the jet through 165° (so β2 = 15°), k = 0.9.

Example 2 - Francis runner from velocity triangles. H = 60 m, N = 600 rpm, Q = 2.5 m³/s, speed ratio 0.65, guide-vane angle α1 = 15°, ηh = 90%, no whirl at exit, ηm = 97%.

Example 3 - Kaplan turbine sizing. Runner tip diameter 3.0 m, hub 1.2 m, H = 18 m, speed ratio 2.0, flow ratio 0.6, ηo = 88%.

Example 4 - Cavitation setting for that Kaplan. Site at 600 m altitude, water at 30 °C (vapour pressure 4.24 kPa).

Example 5 - Unit quantities. A turbine gives 1,000 kW at 300 rpm with Q = 5 m³/s under H = 25 m. Find its behaviour at H = 16 m.

FeaturePeltonFrancisKaplan
ActionImpulseReaction (mixed flow)Reaction (axial)
Head range~250-1,800 m~30-400 m~2-60 m
Specific speed (metric)8-30 (multi-jet to ~70)60-300300-1,000
FlowSmallMediumVery large
Speed ratio φ≈0.460.6-0.91.4-2.0
RegulationSpear + deflectorGuide vanes (single)Vanes + blades (double)
Draft tubeNoneEssentialEssential
Casing pressureAtmosphericSpiral, pressurisedSpiral, pressurised
Cavitation riskNilModerateHigh
Part-load efficiencyFlatFalls sharplyFlat
Indian exampleMoolamattom, Idukki (6 × 130 MW)Nathpa Jhakri (6 × 250 MW), TehriBarrage and canal-drop stations; bulb units on canals

Where it is used

Interview questions

Common mistakes

Related topics

Centrifugal and reciprocating pumps · Dimensional analysis and similitude · Fluid flow: Bernoulli and flow measurement · Viscous flow and pipe losses · Hydraulics and pneumatics · Turbomachinery and power-plant engineering

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