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Rock mechanics and ground control

Mining Engineering (B.E./B.Tech) · Mine operations · free study notes for exams, placements and interviews

In short

Rock mechanics is the study of how rock and rock masses deform and fail under stress; ground control is the engineering use of that knowledge to keep mine roofs, pillars, ribs, benches and dumps standing. Every underground gallery, every pillar left for support, every opencast bench angle and every dump height in India is sized from rock-mass strength, in-situ stress and a factor of safety. It is examined in GATE (Mining Engineering) under "Rock mechanics / ground control" with numerical questions on pillar stress, RMR and slope stability, and in university papers under strata control. Employers — Coal India subsidiaries (ECL, BCCL, CCL, WCL, SECL, MCL, NCL), SCCL, NLC, Hindustan Zinc, Tata Steel, Vedanta, NMDC, Hindustan Copper — test it in interviews for mining engineer, strata-control officer and geotechnical roles, and DGMS requires support design to be backed by it.

Explained

Rock material properties and laboratory tests

In-situ stress and stress around openings

Rock-mass classification

Failure criteria

Underground ground control: pillars, support and caving

Subsidence and surface protection

Opencast slope and dump stability

Instrumentation and monitoring

Key points

Formulas and examples

σv = γH — vertical in-situ stress (MPa); γ = unit weight (MN/m³, ≈0.025), H = depth (m). σh = k σv.
RQD = (Σ lengths of core pieces ≥ 100 mm / total core run) × 100 %
Is = P/De² ; Is50 = Is × (De/50)0.45 ; UCS ≈ (20 to 25) × Is50 — P = failure load (N), De = equivalent core diameter (mm), Is in MPa
Brazilian tensile strength σt = 2P/(πDt) — D = disc diameter, t = thickness (mm), P in N
Mohr-Coulomb: τ = c + σn tanφ ; σ1 = σ3(1+sinφ)/(1−sinφ) + 2c cosφ/(1−sinφ) ; UCS = 2c cosφ/(1−sinφ)
Hoek-Brown (original): σ1 = σ3 + σci √(mb σ3/σci + s)
Tributary area pillar stress (square pillars): σp = γH (w + B)² / w² ; extraction ratio e = 1 − w²/(w+B)²
CMRI (Sheorey) coal pillar strength: S = 0.27 σc h−0.36 + (H/250 + 1)(w/h − 1) MPa — σc = UCS of 25 mm coal cube (MPa), h = seam/pillar height (m), w = pillar width (m), H = depth (m)
Obert-Duvall: Sp = S1(0.778 + 0.222 w/h) ; Bieniawski: Sp = σ1(0.64 + 0.36 w/h)
Factor of safety FoS = pillar strength / pillar stress
Q = (RQD/Jn)(Jr/Ja)(Jw/SRF) ; Barton roof support pressure proof = (2√Jn · Q−1/3)/(3Jr) MPa (conservative; the Q-chart is preferred)
Unal (RMR) support pressure: p = ((100 − RMR)/100) γ B — B = span (m); rock-load height = p/γ
CMRI rock load for coal roof: P = B · γ · (1.7 − 0.037 RMR + 0.0002 RMR²) t/m² — B = gallery width (m), γ in t/m³
Bolt grid: area per bolt A = (bolt safe capacity)/(support pressure); spacing = √A. Bolt length rule of thumb L = 1.4 + 0.184 B (m)
Caving height Hc = m/(k − 1) — m = extracted thickness, k = bulking factor (1.2–1.5)
Subsidence Smax = a · m ; critical panel width ≈ 1.2 to 1.4 H
Planar slope FoS = [cL + (W cosψp − U) tanφ] / (W sinψp), with L = H/sinψp and W = ½γH²(cotψp − cotψf) per metre width
Rock-mass modulus: Em = 2 RMR − 100 (GPa) for RMR > 50 ; Em = 10(RMR−10)/40 GPa generally

Example 1 — RQD and Q from a core run. A 2.0 m run yields intact pieces of 250, 180, 420, 120, 310 and 150 mm (rest fragmented).

Q = (71.5/9) × (1.5/2) × (1/1) = 7.94 × 0.75 = 5.96 ≈ 6 → "fair" rock mass.

Example 2 — point load to UCS. Diametral test on NX core, De = 54 mm, failure load P = 8.5 kN.

Example 3 — triaxial data to c and φ. Triaxial tests give σ1 = 45 MPa at σ3 = 5 MPa and σ1 = 75 MPa at σ3 = 15 MPa.

Example 4 — pillar design (bord-and-pillar). Depth H = 200 m, seam height h = 3 m, gallery B = 4.8 m, γ = 0.025 MN/m³, coal σc = 25 MPa. Trial pillar w = 20 m (square).

Pillar width w (m)Centre distance (m)σp (MPa)S (MPa)FoSExtraction %
1418.89.0111.151.2445
1620.88.4512.351.4641
1721.88.2212.951.5839
2024.87.6914.751.9235

Example 5 — roof-bolt pattern from CMRI RMR. Gallery B = 4.8 m, adjusted RMR = 45, roof γ = 2.5 t/m³.

Example 6 — planar slope failure. Bench H = 12 m, face angle ψf = 60°, joint dipping ψp = 35° and daylighting, c = 25 kPa, φ = 30°, γ = 25 kN/m³, dry (U = 0).

Example 7 — caving and subsidence. Seam m = 3 m, bulking factor k = 1.3, depth 150 m, panel width 200 m, subsidence factor a = 0.6.

Where it is used

Interview questions

Common mistakes

Related topics

Drilling and blasting · Mine planning and design software · Mine ventilation · Mine surveying · Mining methods and pillar extraction · Mine safety legislation and DGMS practice

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