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Water treatment plant design

Civil Engineering (B.E./B.Tech) · Water and environment · free study notes for exams, placements and interviews

In short

Water treatment plant (WTP) design is the sizing and arrangement of unit operations - aeration, coagulation, flocculation, sedimentation, filtration, disinfection and special treatment - that convert raw surface or ground water into water meeting IS 10500:2012 drinking water standards. It matters because the quality of raw water decides the treatment train, and every unit must be hydraulically sized for a design flow with allowance for peak factor and maintenance. It is examined in GATE Civil (Environmental Engineering section, usually 6-10 marks), university Environmental Engineering papers, and in AE/JE and ESE recruitment for state PHE/Water Boards. On the job it is used by Jal Jeevan Mission and AMRUT consultants, L&T, VA Tech Wabag, Tata Projects, SUEZ and state PHED/Jal Nigam engineers who design and commission plants.

Explained

Raw water quality, standards and choice of treatment train

Raw waterTypical train
Clear lake/reservoir, turbidity < 10 NTUScreening → slow sand filter or direct filtration → disinfection
River water, turbidity 10-1000 NTUScreening → aeration (if needed) → coagulation-flocculation → sedimentation → rapid sand filtration → disinfection
Very turbid river (monsoon, > 1000 NTU)Add plain sedimentation / pre-settling tank ahead of coagulation
Groundwater, hardAeration → softening (lime-soda or ion exchange) → filtration → disinfection
Groundwater with Fe/MnAeration → oxidation/contact → filtration → disinfection
Groundwater with F or AsNalgonda (alum) / activated alumina / bone char for F; adsorption or coagulation-filtration for As
Brackish / high TDSPre-treatment → RO → remineralisation → disinfection

Preliminary treatment: screening, aeration, plain sedimentation

Coagulation and flocculation

Sedimentation tank design (type II settling)

Filtration

ParameterSlow sand filterRapid sand filter
Rate (m³/m²/day)2.4-5100-200
Effective size D₁₀ (mm)0.2-0.30.35-0.55
Pre-treatmentPlain sedimentation onlyCoagulation + sedimentation essential
CleaningScrape top 2-3 cm, 1-3 monthsBackwash, 24-72 h
Area neededVery largeSmall
Bacteria removal99.9% (biological)98-99% (needs disinfection)
CostLow capital, low O&M skillHigh capital, skilled O&M

Disinfection

Special treatment and plant layout

Key points

Formulas and examples

Settling velocity (Stokes' law): v = g (ρs − ρw) d² / (18 µ)
v = settling velocity (m/s), g = 9.81 m/s², ρs, ρw = particle and water density (kg/m³), d = particle diameter (m), µ = dynamic viscosity (N·s/m², ≈ 1.002 × 10⁻³ at 20 °C)
Surface overflow rate SOR = Q / A = v₀ ; Detention time t = V / Q ; Horizontal velocity vh = Q / (B × H)
Q = design flow (m³/day or m³/s), A = plan area (m²), V = tank volume (m³), B = width, H = depth (m)
Removal efficiency of a particle with velocity vs < v₀ : η = vs / v₀
Velocity gradient G = √(P / (µ V)) ; Camp number = G × t
P = power dissipated (W), µ = dynamic viscosity (N·s/m²), V = tank volume (m³), t = detention time (s)
Paddle power P = CD × A × ρw × vr³ / 2 ; vr = 0.75 × vp (relative velocity ≈ 0.75 of paddle velocity)
CD = drag coefficient (≈ 1.8 for flat paddles), A = paddle area (m²), vp = peripheral paddle velocity (m/s)
Filter area A = Q / (rate of filtration) ; Number of beds n = A / (area per bed), with one standby
Head loss in a clean filter bed (Rose's equation): hL = 1.067 CD L v² / (φ g e⁴ d)
L = bed depth (m), v = filtration velocity (m/s), e = porosity, d = grain size (m), φ = shape factor
Kozeny equation: hL / L = k µ (1 − e)² S² v / (ρw g e³), with S = specific surface area of grains
Chlorine demand = dose applied − residual chlorine (mg/L) ; Chlorine mass = Q × dose (kg/day, with Q in MLD and dose in mg/L)
Alum requirement (kg/day) = Q (MLD) × dose (mg/L) ; Alkalinity consumed = 0.45 × alum dose ; CO₂ released = 0.40 × alum dose (all mg/L as CaCO₃ basis for alkalinity)

Example 1 - Sizing a sedimentation tank. A town needs 10 MLD average demand. Design a rectangular sedimentation tank at SOR = 30 m³/m²/day and detention 2.5 h.

Example 2 - Removal efficiency and particle size. For the tank above (v₀ = 30 m³/m²/day):

d² = 18 µ v / (g (ρs − ρw)) = (18 × 1.002 × 10⁻³ × 3.472 × 10⁻⁴) / (9.81 × 1650) = 6.262 × 10⁻⁶ / 16,186.5 = 3.868 × 10⁻¹⁰ m². d = 1.967 × 10⁻⁵ m ≈ 0.020 mm (20 µm) - fine silt. Anything finer needs coagulation.

Example 3 - Alum dose, alkalinity and cost. An 18 MLD plant uses alum at 28 mg/L. Raw water alkalinity is 10 mg/L as CaCO₃.

Example 4 - Flocculator design (G, Gt and paddle power). Design a flocculation tank for 18 MLD with t = 30 min and G = 40 /s; µ = 1.002 × 10⁻³ N·s/m².

vr³ = 2P/(CD A ρ) = (2 × 601)/(1.8 × 8 × 998) = 1202/14,371 = 0.0836 → vr = 0.437 m/s. Peripheral paddle speed vp = vr/0.75 = 0.58 m/s (within the 0.2-0.6 m/s guide); for a paddle of radius 1.5 m, N = 0.58/(2π × 1.5) = 0.062 rev/s ≈ 3.7 rpm.

Example 5 - Rapid sand filters and backwash. Same 18 MLD plant; filtration rate 5,000 L/m²/h (= 5 m/h = 120 m³/m²/day).

UnitKey design parameterTypical Indian value (CPHEEO)
Flash mixerDetention / G30-60 s / 300-1000 /s
FlocculatorDetention / G / Gt20-40 min / 10-75 /s / 10⁴-10⁵
ClarifierSOR / detention / depth20-40 m³/m²/day / 2-4 h / 3-4.5 m
Tube settlerSOR on plan area40-60 m³/m²/day
Rapid sand filterRate / D₁₀ / bed depth100-200 m³/m²/day / 0.35-0.55 mm / 0.6-0.75 m
Slow sand filterRate / D₁₀2.4-5 m³/m²/day / 0.2-0.3 mm
Chlorine contactTime / residual≥ 30 min / 0.2 mg/L at tap

Where it is used

Interview questions

Common mistakes

Related topics

Water supply engineering · Wastewater engineering · Sewer network design · Rainwater harvesting and water conservation · Groundwater hydraulics · Environmental impact assessment

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