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BJT and MOSFET

Electronics and Communication Engineering (B.E./B.Tech) · Circuits and devices · free study notes for exams, placements and interviews

In short

The bipolar junction transistor (BJT) and the metal-oxide-semiconductor field-effect transistor (MOSFET) are the two three-terminal devices on which all analog and digital electronics is built. A BJT is a current-controlled device in which a small base current controls a large collector current; a MOSFET is a voltage-controlled device in which the gate-source voltage controls the channel current through an insulating oxide. Every amplifier, switch, logic gate, SMPS, motor drive and VLSI chip reduces to one of these two, so the topic carries the largest single share of marks in GATE EC/IN, ESE, ISRO, DRDO and BARC papers and is the standard opening round in placement interviews at Texas Instruments, Analog Devices, Qualcomm, Intel, NXP, Bosch, Cadence, Synopsys, Tata Elxsi and Tejas Networks. It is examined as device physics (structure, regions, characteristics), as DC analysis (Q-point, load line) and as a switch (saturation, conduction loss).

Explained

BJT: structure, operation and regions

RegionEB junctionCB junctionUse
Cut-offReverseReverseOFF switch, I_C ≈ I_CEO
ActiveForwardReverseLinear amplifier, I_C = βI_B
SaturationForwardForwardON switch, V_CE(sat) ≈ 0.2 V
Reverse-activeReverseForwardRarely used, very low gain

BJT: configurations, characteristics and second-order effects

ConfigurationCurrent gainVoltage gainR_inR_outTypical use
Common base (CB)α < 1HighVery low (tens of Ω)HighRF stage, current buffer
Common emitter (CE)β (high)High, invertingModerate (kΩ)ModerateGeneral amplifier, switch
Common collector (CC, emitter follower)1+β≈ 1, non-invertingVery highVery lowBuffer, impedance matching

BJT biasing, DC load line and the transistor as a switch

MOSFET: structure, threshold and operation

MOSFET types, characteristics and second-order effects

Small-signal parameters and BJT versus MOSFET

FeatureBJTMOSFET
ControlCurrent (I_B); input power neededVoltage (V_GS); no DC gate current
CarriersBoth electrons and holes (bipolar)One type (unipolar)
Transfer lawExponential, I_C = I_S eV_BE/V_TSquare law, I_D = ½k'(W/L)V_OV²
g_m at same currentHigher (I_C/V_T)Lower (2I_D/V_OV)
Input impedancekΩ rangeVery high (10¹²-10¹⁵ Ω)
ON-state drop (switch)V_CE(sat) ≈ 0.2-0.5 V, fixedI_D·R_DS(on), scalable to mΩ
Temperature coefficientNegative (thermal runaway, no easy paralleling)Positive R_DS(on) (parallels easily)
NoiseLower 1/f noiseLower shot/base noise; higher 1/f
Offset and matchingBetter matched for a given areaWorse; needs larger area
Integration densityLowerVery high — basis of VLSI/CMOS
Storage time / speedStorage delay in saturationCharge/discharge gate capacitance
Static power in logicAlways someNear zero in CMOS (plus leakage)

Key points

Formulas and examples

I_E = I_B + I_C ; I_C = βI_B ; I_C = αI_E ; β = α/(1−α) ; α = β/(1+β) ; I_CEO = (1+β)I_CBO
I_C = I_S·exp(V_BE/V_T)·(1 + V_CE/V_A) — I_S = saturation current (A), V_T = kT/q ≈ 26 mV at 300 K, V_A = Early voltage (V)
Voltage-divider bias: V_TH = V_CC·R2/(R1+R2) ; R_TH = R1‖R2 ; I_B = (V_TH − V_BE)/(R_TH + (1+β)R_E) ; V_CE = V_CC − I_C R_C − I_E R_E
Stability factor S = (1+β)(R_TH+R_E)/(R_TH+R_E+βR_E)
BJT small signal: g_m = I_C/V_T (A/V = S) ; r_π = β/g_m = βV_T/I_C (Ω) ; r_o = V_A/I_C (Ω) ; intrinsic gain g_m r_o = V_A/V_T
MOSFET triode (V_DS < V_OV): I_D = k'_n(W/L)[V_OV·V_DS − V_DS²/2] ; r_DS(on) ≈ 1/[k'_n(W/L)V_OV]
MOSFET saturation (V_DS ≥ V_OV): I_D = ½k'_n(W/L)V_OV²(1 + λV_DS) ; k'_n = µ_nC_ox (A/V²)
MOSFET small signal: g_m = k'_n(W/L)V_OV = 2I_D/V_OV = √(2k'_n(W/L)I_D) ; r_o = 1/(λI_D) ; g_mb = χg_m
Body effect: V_T = V_T0 + γ(√(2φ_F + V_SB) − √(2φ_F)) ; γ in V½
Switch losses: P_cond(BJT) = V_CE(sat)·I_C ; P_cond(MOSFET) = I_D²·R_DS(on) ; P_sw ≈ ½V·I·(t_on+t_off)·f_s ; T_J = T_A + P·θ_JA (°C/W)

Example 1 — BJT currents and leakage. A transistor has β = 100 and I_B = 20 µA.

Example 2 — Voltage-divider bias, Q-point and small-signal parameters. V_CC = 12 V, R1 = 47 kΩ, R2 = 10 kΩ, R_C = 2.2 kΩ, R_E = 1 kΩ, β = 150, V_BE = 0.7 V.

  1. V_TH = 12 × 10/57 = 2.105 V; R_TH = 47×10/57 = 8.246 kΩ.
  2. I_B = (2.105 − 0.7)/(8.246k + 151 × 1k) = 1.405/159.25k = 8.82 µA.
  3. I_C = 150 × 8.82 µA = 1.323 mA; I_E = 151 × 8.82 µA = 1.332 mA.
  4. V_CE = 12 − (1.323 × 2.2) − (1.332 × 1) = 12 − 2.912 − 1.332 = 7.76 V → safely in the active region.
  5. g_m = 1.323 mA/26 mV = 50.9 mA/V; r_π = 150/50.9 mA/V = 2.95 kΩ; with V_A = 100 V, r_o = 100/1.323 mA = 75.6 kΩ; intrinsic gain g_m r_o ≈ 3,850.
  6. S = 151 × 9.246/159.246 = 8.77 — good stability (fixed bias would give S ≈ 151).

Example 3 — NMOS in both regions. k'_n = 200 µA/V², W/L = 10, V_T = 0.7 V, V_GS = 2 V, λ = 0.02 V⁻¹. So V_OV = 1.3 V and k'_n(W/L) = 2 mA/V².

Example 4 — BJT as a switch. V_CC = 5 V, R_C = 1 kΩ, R_B = 10 kΩ, β(min) = 100, V_in = 5 V, V_BE = 0.7 V, V_CE(sat) = 0.2 V.

  1. I_B = (5 − 0.7)/10 kΩ = 0.43 mA.
  2. I_C(sat) = (5 − 0.2)/1 kΩ = 4.8 mA → I_B(min) = 4.8/100 = 48 µA.
  3. 0.43 mA ≫ 48 µA, so the device is saturated; overdrive factor = 0.43/0.048 ≈ 9, forced β = 4.8/0.43 ≈ 11.
  4. Dissipation in the transistor = 0.2 V × 4.8 mA ≈ 0.96 mW.

Example 5 — Power switch conduction loss, MOSFET versus BJT. A 10 A DC load at 24 V.

Where it is used

Interview questions

Common mistakes

Related topics

FET amplifiers and biasing · Amplifiers and feedback · Semiconductor physics: energy bands, carriers and junctions · Semiconductor diodes and applications · Multistage and differential amplifiers · Power amplifiers

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