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Electric heating and welding

Electrical and Electronics Engineering (B.E./B.Tech) · Practice · free study notes for exams, placements and interviews

In short

Electric heating converts electrical energy into heat inside the work itself or in a resistor near it, and electric welding uses that heat to melt and join metals. Both are standard chapters of "Utilization of Electrical Energy" in Indian B.E./B.Tech electrical syllabi and appear in GATE-EE utilization questions, in state-utility and PSU recruitment papers (SSC-JE, RRB-JE, DMRC, NTPC, SAIL, BHEL) and in diploma practicals. The subject matters industrially because electric arc and induction furnaces make most of India's secondary steel, and resistance and arc welding hold together every fabricated structure, pipeline and car body. Numerical work centres on heating-element design, furnace energy balances, duty cycle and welding-transformer ratings.

Explained

Why electric heating, and how it is classified

Resistance heating and element design

Arc furnaces

Induction and dielectric heating

Electric welding: processes and equipment

Resistance welding and the Indian standards framework

Key points

Formulas and examples

Heat produced H = I²Rt joules = V²t/R; 1 kWh = 3.6 × 10⁶ J = 860 kcal
Heat required Q = m·c·(θ₂ − θ₁) + m·L (m = mass kg, c = specific heat kJ/kg·°C, L = latent heat of fusion kJ/kg)
Resistance R = ρL/A (ρ = resistivity Ω·m, L = length m, A = cross-section m²); for round wire A = πd²/4
Efficiency η = heat usefully absorbed by charge / electrical energy input
Radiant heat exchange H = 5.67 × e × K × [(T₁/100)⁴ − (T₂/100)⁴] W/m² (T in kelvin, e = emissivity, K = radiation factor)
Star/delta and series/parallel power ratios: P(delta) = 3 × P(star); P(parallel) = 4 × P(series)
Welding heat input (per unit length) = (V × I × 60) / (v × 1000) kJ/mm, v = travel speed mm/min
Permissible current at new duty cycle: I₂ = I₁ √(D₁/D₂)
Welding set kVA = V_oc × I / 1000 (single phase); input power = V·I·cosφ; η = arc power / input power

Example 1 — Resistance oven element design. A resistance oven is to take 16 kW at 230 V single phase, three elements in parallel, using Ni-Cr wire of resistivity 1.1 × 10⁻⁶ Ω·m. Element temperature 1,000 °C, charge 500 °C, emissivity 0.9, radiation factor 0.6. Find wire diameter and length per element.

Example 2 — Furnace energy and efficiency. An electric furnace melts 1,000 kg of brass from 25 °C. Specific heat 0.39 kJ/kg·°C, melting point 920 °C, latent heat 168 kJ/kg; furnace efficiency 70%. Energy at ₹8.00/kWh.

Example 3 — Welding transformer and power factor. A single-phase AC welding set draws from a 415 V supply and delivers 300 A at an arc voltage of 25 V. Input power measured 9.0 kW.

Example 4 — Spot welding and duty cycle. Two 1.5 mm steel sheets are spot welded with 8,000 A for 10 cycles (50 Hz) with an interface resistance of 100 µΩ.

Example 5 — Star/delta temperature control. Three 1 kΩ elements supplied at 400 V three phase.

FeatureResistance heatingInduction heatingDielectric heatingArc heating
ChargeConductorConductorInsulatorConductor
Frequency50 Hz50 Hz to 450 kHz10–50 MHz50 Hz or DC
Heat sourceI²R in element/chargeEddy current + hysteresis in chargeDielectric lossArc at 3,000 °C+
Typical useOvens, water heaters, salt bathMelting, surface hardening, brazingPlywood, textiles, plasticsSteel melting, ferro-alloys
TemperatureUp to ~1,350 °CUp to ~2,000 °CLow (below ~200 °C)Very high
FeatureArc weldingResistance welding
Heat sourceArc between electrode and workI²R at the interface
Voltage / current15–30 V arc, 50–600 A1–30 V, 2,000–50,000 A
PressureNot appliedEssential
FillerUsually requiredNone
SkillHighLow, machine-set
SuitsThick sections, site work, any positionThin sheet, mass production

Where it is used

Interview questions

Common mistakes

Related topics

Illumination engineering and lighting design · Electric traction and drives · Energy audit and conservation · Power quality, harmonics and reactive compensation · Testing and commissioning of electrical equipment · Electrical safety and earthing

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