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Energy audit and conservation

Electrical and Electronics Engineering (B.E./B.Tech) · Practice · free study notes for exams, placements and interviews

In short

An energy audit is the systematic measurement, accounting and analysis of energy flows in a facility to identify where energy is wasted and to quantify cost-effective measures to reduce it; energy conservation is the implementation of those measures. In India it rests on a statutory base - the Energy Conservation Act 2001 (amended 2010 and 2022), which created the Bureau of Energy Efficiency (BEE), notified Designated Consumers, and made periodic audits by Accredited Energy Auditors mandatory for them. Electrical engineers are examined on it in university electives on Energy Audit and Management, in GATE/UPSC-ESE questions on tariffs, power factor and efficiency, and most heavily in the BEE Energy Manager/Energy Auditor certification. It is used daily by utilities, ESCOs, manufacturing plants, PWD/CPWD building projects, data centres and EPC firms.

Explained

Definitions, scope and legal framework

Types of energy audit

Step-by-step audit methodology (ten steps, BEE approach)

  1. Phase I - Pre-audit: plan the visit, form the team, organise instruments, discuss scope and economic criteria with management, and get a first feel for the plant.
  2. Collect historical data: 12-24 months of electricity bills, fuel purchases, production figures; compute baseline SEC, load factor, power factor and maximum demand.
  3. Prepare process flow and energy flow diagrams with input-output boundaries for each section/cost centre.
  4. Phase II - Measurement: log power, current, voltage, PF, flow, pressure, temperature, flue gas composition, speed, light level and steam parameters at each major load.
  5. Build the energy balance: account for every input against useful output plus losses; close the balance within an acceptable error band and explain the gap.
  6. Identify Energy Conservation Opportunities (ENCONs): compare measured efficiency with design and with benchmarks; list wasteful practices, oversizing, throttling, leaks, idling.
  7. Technical and economic evaluation: quantify annual savings in kWh, kL, tonnes and rupees; estimate investment; compute simple payback, NPV, IRR and sometimes cost of conserved energy.
  8. Prioritise and categorise: no-cost/housekeeping, low-cost/short payback (< 1 year), medium (1-3 years) and high-investment/long payback measures.
  9. Phase III - Reporting: submit the report with executive summary, baseline, recommendations, savings, investment, payback and implementation plan; present it to management.
  10. Implementation and Measurement & Verification (M&V): execute, then verify savings against the adjusted baseline (IPMVP options A-D) and institutionalise monitoring and targeting (M&T).

Instruments and measurements

Energy conservation opportunities - electrical side

Energy conservation opportunities - thermal side

Economics, benchmarking and reporting

Key points

Formulas and examples

Specific Energy Consumption SEC = Total energy input / Production output (kWh/tonne, kcal/kg, kWh/m²)
Energy Performance Index EPI = Annual energy consumption (kWh) / Built-up area (m²) per year
Load factor LF = Average load / Maximum demand = kWh in period / (MD in kW × hours)
Power factor pf = P(kW)/S(kVA) = cos φ; kVAr required = P (tan φ₁ − tan φ₂), φ₁ = existing, φ₂ = target angle
Three-phase power P = √3 × V_L × I_L × cos φ (watt, V in volt, I in ampere)
Motor input and output P_in = P_out/η; P_out = (% loading) × rated kW
Affinity laws Q₂/Q₁ = N₂/N₁; H₂/H₁ = (N₂/N₁)²; P₂/P₁ = (N₂/N₁)³
Pump shaft power P (kW) = ρ g Q H / (1000 η_pump) with ρ in kg/m³, Q in m³/s, H in m, g = 9.81 m/s²
Fan shaft power P (kW) = Q(m³/s) × Δp(Pa) / (1000 × η_fan)
Boiler efficiency, direct method η = Q_steam × (h_steam − h_feedwater) / (Q_fuel × GCV) × 100
Indirect method η = 100 − (all percentage losses: dry flue gas, H₂ in fuel, moisture, CO, radiation, unburnt)
Transformer efficiency η = x·S·cos φ / (x·S·cos φ + P_iron + x²·P_copper), x = per-unit loading, S = rating in kVA
Maximum efficiency loading x = √(P_iron / P_copper,full-load)
Simple payback SPP (years) = Capital investment (₹) / Annual net saving (₹/year)
NPV = Σ [Cash flow_t / (1+i)t] − Investment; IRR is the discount rate i making NPV = 0
Heat loss / recovery Q = m × c_p × ΔT (kJ), with m in kg, c_p in kJ/kg·K, ΔT in K
Cost of conserved energy CCE = (Investment × annualisation factor) / Annual energy saved (₹/kWh)

Example 1 - Power factor improvement and payback. A plant draws 500 kW at 0.75 lagging power factor. The tariff charges ₹350 per kVA of billed demand per month, and billing is on kVA. Capacitors cost ₹400 per kVAr installed. Find the kVAr needed to raise PF to 0.96, the monthly saving and the simple payback.

Example 2 - VFD on a centrifugal pump (affinity laws). A 55 kW pump motor runs continuously at 90% of rated shaft load with a discharge valve throttled to deliver 80% of full flow. A VFD would instead reduce speed to 80%. Energy cost ₹8/kWh, 8,000 running hours/year, VFD cost ₹2,75,000.

Example 3 - Transformer loading and maximum efficiency. A 1,000 kVA distribution transformer has iron loss 1.6 kW and full-load copper loss 10 kW; load power factor is 0.9.

Example 4 - Lighting retrofit with load factor check. An assembly hall has 240 fittings of 2 × 36 W fluorescent tubes with 10 W magnetic ballast loss per tube, running 10 h/day, 300 days/year. They are replaced by 240 LED battens of 40 W each. Energy cost ₹7.50/kWh; retrofit cost ₹1,200 per batten.

Example 5 - Boiler efficiency and economiser saving (direct method). A boiler generates 8 tonnes/hour of steam at enthalpy 2,760 kJ/kg from feedwater at 85 °C (enthalpy 356 kJ/kg), burning 700 kg/h of furnace oil of GCV 42,000 kJ/kg at ₹55/kg, for 7,000 h/year.

MeasureTypical savingTypical paybackCategory
Fix compressed air leaks5-20% of compressor energyImmediate - 3 monthsNo/low cost
Reduce compressor discharge pressure by 1 bar7-8% of compressor powerImmediateNo cost
Capacitors for power factorDemand charge + loss reduction3-12 monthsLow cost
LED lighting retrofit40-60% of lighting energy1-2 yearsLow-medium
VFD on throttled pump/fan20-50% of drive energy6 months - 2 yearsMedium
IE3/IE4 motor replacement2-6% of motor energy1-3 yearsMedium
Boiler economiser / air pre-heater4-8% fuel3 months - 1.5 yearsMedium
Waste heat recovery / cogeneration10-30% of fuel bill2-5 yearsHigh
AspectPreliminary auditDetailed audit
Data sourceBills, nameplates, interviewsDirect measurement and logging
Duration1-3 days1-10 weeks
Accuracy of savings±20-30%±5-10%
OutputScope and quick winsEnergy balance, costed ENCON list, action plan
UseScreening and management buy-inInvestment decisions, ESCO contracts, statutory compliance

Where it is used

Interview questions

Common mistakes

Related topics

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