Knowledge / Electrical and Electronics Engineering / Overhead line design: sag, tension and insulators

Overhead line design: sag, tension and insulators

Electrical and Electronics Engineering (B.E./B.Tech) · Power systems · free study notes for exams, placements and interviews

In short

Overhead line design fixes how much a conductor dips between two supports (sag), the tension it is strung at, and the insulators that hold it clear of the earthed structure. Sag and tension are inverse: low sag needs high tension, which risks conductor failure; high sag needs taller towers and wider right-of-way, and both are bounded by statutory ground clearance. Insulator design decides the flashover withstand of the line and its behaviour under pollution. The topic is examined in Power Systems I / Transmission and Distribution papers and in GATE (EE), and is daily work in transmission design at POWERGRID, state transcos, L&T, Kalpataru, Sterlite Power and KEC, governed by IS 802, IS 5613, IS 398, IS 731 and the CEA safety regulations under the Electricity Act, 2003.

Explained

Conductors, supports and loading conditions

Sag of a freely suspended conductor

Effect of ice and wind

Change of state, sag templates and stringing

Insulators: types and materials

Voltage distribution in a string and string efficiency

Key points

Formulas and examples

S = w L² / (8 T) - sag for supports at equal level; w = load per unit length (kg/m or N/m), L = span (m), T = horizontal tension (kg or N), S = sag (m)
y = c [cosh(x/c) − 1], c = T/w - exact catenary; S = c[cosh(L/2c) − 1]
x₁ = L/2 − T h/(w L); x₂ = L/2 + T h/(w L); S₁ = w x₁²/(2T); S₂ = w x₂²/(2T) - unequal supports, h = level difference (m)
wᵢ = ρᵢ π t (d + t) - ice load per metre; t = radial ice thickness, d = conductor diameter, ρᵢ ≈ 910 kg/m³
w_w = P (d + 2t) - wind load per metre; P = design wind pressure (kg/m² or N/m²)
w_t = √[(w + wᵢ)² + w_w²]; θ = tan⁻¹[w_w/(w + wᵢ)]; vertical sag = (w_t L²/8T) cos θ
T_max = UTS / FoS; conductor length ℓ ≈ L + 8S²/(3L)
T₂³ − K T₂² = A E w₂² L² / 24, where K = T₁ − A E α (t₂ − t₁) − A E w₁² L²/(24 T₁²) - change-of-state (parabolic) equation; A = area, E = modulus, α = coefficient of linear expansion
L_eq = √(Σ L³ / Σ L) - equivalent (ruling) span
V₂ = V₁(1+k); V₃ = V₁(1+3k+k²); η_string = V_string /(n × V_n) × 100% - k = earth/self capacitance ratio, n = number of discs

Example 1 - sag with ice and wind. Span 300 m, conductor diameter 2.0 cm, weight 1.20 kg/m, UTS 8,000 kg, FoS 2, radial ice 1.0 cm (ρ = 910 kg/m³), wind pressure 39 kg/m² on projected area.

Example 2 - supports at unequal level. Same conductor (w = 1.2 kg/m, T = 4,000 kg), span 300 m, level difference h = 8 m.

Example 3 - effect of temperature (change of state). Span 250 m, A = 3 cm², w = 1.0 kg/m, E = 0.8 × 10⁶ kg/cm², α = 18 × 10⁻⁶/°C, tension 2,000 kg at 15 °C. Find tension and sag at 50 °C (no wind).

Example 4 - string efficiency and grading. A 3-disc suspension string, k = 0.2, total string voltage 38.4 kV.

Example 5 - equivalent span and conductor length. Section spans 200, 250, 300, 350 m.

FeaturePin insulatorSuspension (disc) stringStrain insulator
PositionUpright on cross-arm pinHangs from cross-armHorizontal at dead-end
Voltage rangeUp to ~33 kV66 kV and aboveAny, as per line
Main loadConductor weight + windWeight + wind swingFull conductor tension
Failure handlingWhole unit replacedSingle disc replacedParallel strings share load
Cost at EHVUneconomic, bulkyEconomical, modularEconomical

Where it is used

Interview questions

Common mistakes

Related topics

Transmission lines and cables · High-voltage engineering and insulation · Distribution systems and substations · Power quality and harmonics · Power system protection: relays and circuit breakers · Electricity markets and regulation in India

Open in the Knowledge reader →Find jobs →